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Kazeer [188]
3 years ago
15

Suppose you have a bag containing 2 black marbles and 3 red marbles. You reach into the bag, select a marble, see what color it

is and replace it in the bag. Then you repeat this process a second time. What is the probability of picking a red marble both times?
Mathematics
1 answer:
TiliK225 [7]3 years ago
3 0

Answer:

\dfrac{9}{25}

Step-by-step explanation:

Given that the bag contains black and red marbles.

Number of black marbles in the bag = 2

Number of red marbles in the bag = 3

Total number of marbles in the bag = Number of black marbles + Number of red marbles = 2 + 3 = 5

Let us have a look at the formula for probability of an event E, which can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(\text{First red marble}) = \dfrac{\text{Number of red marbles}}{\text{Total number of marbles}} = \dfrac{3}{5 }

Now, the marble chosen at first is replaced.

Therefore, the count remains the same.

P(\text{Second red marble}) = \dfrac{\text{Number of red marbles}}{\text{Total number of marbles}} = \dfrac{3}{5}

Now, the <em>required probability</em> can be found as:

P(\text{First red marble})\times P(\text{Second red marble}) = \dfrac{3}{5}\times \dfrac{3}{5} = \bold{\dfrac{9}{25} }

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Answer:

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2 years ago
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3 years ago
What is 1/10th of 2,871,000?
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