Answer:
One witch is straight across
Step-by-step explanation:
Hey there!
3^15/ 3^3
3^15
= 3*3*3*3*3*3*3*3*3*3*3*3*3*3*3
= 9*9*9*9*9*9*9*3
= 81*81*81*27
= 6,561 * 2,187
= 14,348,907
= 14,348,907/3^3
3^3
= 3*3*3
= 9*3
= 27
14,348,907/27
= 531,441
15 - 3 = 12
= 3^12
Because
3^12
= 3*3*3*3*3*3*3*3*3*3*3*3
= 9*9*9*9*9*9
= 81*81*81
= 6,561*81
= 531,441
531,441 ≈ 3^12
Therefore, your answer should be: 3^12
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
Okay for problem 1 heres my explanation
So if you can get 4 bags for 5 cents so I multiplied 5 by 5 to get 25 cents and multiplied 4 by 5 and got 20 for 25 cents but the machine sells you 9 for 25 cents so if you get the m&ms from Jeanie you'll get more for your money if you get it from jeanie
Now problem 2
Now if tom sells 10 cards for 35 cents so theres a 5 cent difference for 2 more cards now 3 cents will be the most likley for the price for one of toms cards and toms price should have been 33 cents so your only being robbed of 2 cents not a big amount but we'll still look at the other guy 12 cards for 40 cents now if we look at how much toms cards will be if you bought 12 is only 39 cents 1 cent less than the other guy so in conclusion if you buy from Tom you get the better buy
Now problem 3
simple mutipily 19x4 and 76 cents the guys at the firework stands charge 85 for four so if you go to the hardware store and buy your fireworks there you get a better deal.
okay so im running out of time so someone else is gonna answer the last problem... sorry m8
The answer will be -938,988.
The reason the answer is still negative is because its has got be added to more than 941,157 to be positive.
If you need further assistance, please just ask me:)
Thank u & have a great rest day☺️
Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way
Step-by-step explanation:
- From a standard deck of cards, one card is drawn. What is the probability that the card is black and a
jack? P(Black and Jack) P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26
- A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen
or an ace.
P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13
- WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the probability that they will both be aces?
P(AA) = (4/52)(3/51) = 1/221.
- WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a king?
P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been removed.
- WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the
probability of drawing the first queen which is 4/52.
- The probability of drawing the second queen is also 4/52 and the third is 4/52.
- We multiply these three individual probabilities together to get P(QQQ) =
- P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
- Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)
