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AleksandrR [38]

3 years ago

15

A pizza place offers 3 different cheeses and 12 different toppings. In how many ways can a pizza be made with 1 cheese and 3 top

pings?

1 answer:

svetlana [45]3 years ago

3 0

You have to choose 1 sort of cheese from 3 ( 3 ways ). Also you have to choose 3 toppings from 12 different toppings:
12 * 11 * 10 = 1,320 ways.
In total: 3 * 1,320 = 3,960
Answer:
In 3,690 ways can pizza be made with 1 cheese and 3 toppings.

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Find the x-intercept and the y-intercept for the graph of the equation x+y=7

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All of them are wrong except for the third one

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Which is the equation of a hyperbola with directrices at x = ±3 and foci at (4, 0) and (−4, 0)?

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Answer:

$\frac{x^2}{12}-\frac{y^2}{4}=1$

Step-by-step explanation:

Since our foci are located on the x-axis, then our major axis is going to be the horizontal transverse axis of the hyperbola:

<u>Formula for hyperbola with horizontal transverse axis centered at origin</u>

<u /> $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$
Directrices -> $x=\pm\frac{a^2}{c}$
Foci -> $(\pm c,0)$ where $a^2+b^2=c^2$
$a>b$

Since we are given our directrices of $x=\pm3$ and foci of $(\pm4,0)$ , then we can set up the directrices equation to solve for $a^2$ :

$x=\pm\frac{a^2}{c}\\ \\\pm3=\pm\frac{a^2}{4}\\ \\12=a^2$

Now we can determine $b^2$ to complete our equation for the hyperbola:

$a^2+b^2=c^2\\\\12+b^2=4^2\\\\12+b^2=16\\\\b^2=4$

Therefore, our equation for our hyperbola is $\frac{x^2}{12}-\frac{y^2}{4}=1$

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In ΔABC, AD and BE are the angle bisectors of ∠A and ∠B and DE ║ AB . If m∠ADE is with 34° smaller than m∠CAB, find the measures

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Step-by-step explanation:

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4 is too low, 90 cant be divided by 8 and 160 is the only answer even though it is highest number

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A driving exam consists of 29 multiple-choice questions. Each of the 29 answers is either right or wrong. Suppose the probabili

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Answer and explanation:

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Let X be the number of mistake

$P(X$

$P(6\leq X\leq 20)=0.53$

To find : The probability of each of the following outcomes.

a) A student makes more than 20 mistakes

i.e. $P(X>20)$

$P(X>20)=1-P(X\leq 20)$

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b. A student makes 6 or more mistakes

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c. A student makes at most 20 mistakes

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$P(X\leq 20)=1-0.21$

$P(X\leq 20)=0.79$

d. Which two of these three events are complementary?

The complement of an event happening is the exact opposite: the probability of it not happening.

According to definition,

Option a and c are complementary events.

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