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almond37 [142]
3 years ago
12

Mr. Perez went to his favorite restaurant for lunch. his lunch cost $15.00. what was the total bill if yes left a 20% tip?

Mathematics
1 answer:
Mamont248 [21]3 years ago
7 0
To find how much you paid for the tip, take the price of the meal and multiply by the tip rate (presented as a decimal)
so 15×.2 will equal what tip you pay
then just add that to the price of the meal
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Write an expression to represent: Nine minus the quotient of two and a number x.
labwork [276]

Answer:

9 - 2/x

Step-by-step explanation:


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Thomas's cat, Rainwright, eats 0.8 cans of food every day. How much will Thomas spend on food in one week if each can costs $1.7
marshall27 [118]
1 week = 7 days
0.8 \times 7 \times 1.75 \\  = 9.8

Answer : Thomas spends $9.80 on food in one week.

Hope this helps. - M
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3 years ago
The measure of ∠AKG is 133°. What is m∠AKD?
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3 years ago
Find a factorization of x² + 2x³ + 7x² - 6x + 44, given that<br> −2+i√√7 and 1 - i√/3 are roots.
Levart [38]

A factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

<h3>What are the properties of roots of a polynomial?</h3>
  • The maximum number of roots of a polynomial of degree n is n.
  • For a polynomial with real coefficients, the roots can be real or complex.
  • The complex roots of a polynomial with real coefficients always exist in a pair of conjugate numbers i.e., if a+ib is a root, then a-ib is also a root.

If the roots of the polynomial p(x)=ax^4+bx^3+cx^2+dx+e are r_1,r_2,r_3,r_4, then it can be factorized as p(x)=(x-r_1)(x-r_2)(x-r_3)(x-r_4).

Here, we are to find a factorization of p(x)=x^4+2x^3+7x^2-6x+44. Also, given that -2+i\sqrt{7} and 1-i\sqrt{3} are roots of the polynomial.

Since p(x)=x^4+2x^3+7x^2-6x+44 is a polynomial with real coefficients, so each complex root exists in a pair of conjugates.

Hence, -2-i\sqrt{7} and 1+i\sqrt{3} are also roots of the given polynomial.

Thus, all the four roots of the polynomial p(x)=x^4+2x^3+7x^2-6x+44, are: r_1=-2+i\sqrt{7}, r_2=-2-i\sqrt{7}, r_3=1-i\sqrt{3}, r_4=1+i\sqrt{3}.

So, the polynomial p(x)=x^4+2x^3+7x^2-6x+44 can be factorized as follows:

\{x-(-2+i\sqrt{7})\}\{x-(-2-i\sqrt{7})\}\{x-(1-i\sqrt{3})\}\{x-(1+i\sqrt{3})\}\\=(x+2-i\sqrt{7})(x+2+i\sqrt{7})(x-1+i\sqrt{3})(x-1-i\sqrt{3})\\=\{(x+2)^2+7\}\{(x-1)^2+3\}\hspace{1cm} [\because (a+b)(a-b)=a^2-b^2]\\=(x^2+4x+4+7)(x^2-2x+1+3)\\=(x^2+4x+11)(x^2-2x+4)

Therefore, a factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

To know more about factorization, refer: brainly.com/question/25829061

#SPJ9

3 0
1 year ago
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SOMEONE PLEASE I NEED HELL AND I WANT TO GO TO SLEEP, but there’s more than one answer btw
ira [324]

Answer:

The second one, third one and the fifth one should be correct. (7 to the 18th power divided 7 to the 9th power, 7 to the 3rd power to the 3rd power, and 7 to the 4th power times 7 to the 5th power)

Step-by-step explanation:

7 to the 8th power times 7 equal 40353607 so if you do all the equations shown you can rule out which ones equal 40353607 and which ones don't. Have a nice sleep!

3 0
3 years ago
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