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3 years ago

Solve for P P/15=20/25

Mathematics

2 answers:

drek231 [11]3 years ago

6 0

Answer:

p=12

Step-by-step explanation:

Oksanka [162]3 years ago

5 0

Cross multiply in order to get answer

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45.Erica Glaser deposits a check for $20,005.00 and $1.234.00 in cash. What is het total

Gwar [14]

Her total is $21,239

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2 years ago

3. Find two possible lengths for CD if C, D, and E

Kaylis [27]

Given :

C, D, and E are col-linear, CE = 15.8 centimetres, and DE= 3.5 centimetres.

To Find :

Two possible lengths for CD.

Solution :

Their are two cases :

When D is in between C and E .

. . .

C D E

Here, CD = CE - DE

CD = 15.8 - 3.5 cm

CD = 12.3 cm

When E is in between D and C.

. . .

D E C

Here, CD = CE + DE

CD = 15.8 + 3.5 cm

CD = 19.3 cm

Hence, this is the required solution.

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3 years ago

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Marta_Voda [28]

Max will be missing $1.78 in his account. Is that one of the fee choices?

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3 years ago

Read 2 more answers

A toy train car is 6 in. long. If a real train car is 75 ft long, which of the following have the same constant of proportionali

Rus_ich [418]

Answer:

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Step-by-step explanation:

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3 0

3 years ago

Please solve these questions for me. i am having a difficult time understanding.

s2008m [1.1K]

Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

$\angle AED = \angel BEC$ ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

Refer the attached figure

$\angle ABC = 90^{\circ}$

In ΔDBC

BC=DC (Given)

So, $\angle CDB=\angle DBC$ (Opposite angles of equal sides are equal)

So, $\angle CDB=\angle DBC=x$

So, $\angle CDB+\angle DBC+\angle BCD = 180^{\circ}$ (Angle sum property)

x+x+50=180

2x+50=180

2x=130

x=65

So, $\angle CDB=\angle DBC=x = 65^{\circ}$

Now,

$\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90$

So, $\angle ABD=90-x=90-65=25^{\circ}$

In ΔABD

AB = BD (Given)

So, $\angle BAD=\angle BDA$ (Opposite angles of equal sides are equal)

So, $\angle BAD=\angle BDA=y$

So, $\angle BAD+\angle BDA+\angle ABD = 180^{\circ}$ (Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

8 0

3 years ago