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3 years ago

Solve for P P/15=20/25

Mathematics

2 answers:

drek231 [11]3 years ago

6 0

Answer:

p=12

Step-by-step explanation:

Oksanka [162]3 years ago

5 0

Cross multiply in order to get answer

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The line through (6,-6) with slope 1/2 in point-slope form ?

aleksandrvk [35]

Answer: $y + 6 = \frac{1}{2}(x - 6)$

Step-by-step explanation:

Point-slope formula: $y - y1 = m(x - x1)$

Plug in the numbers: $y - -6 = \frac{1}{2}(x-6)$

Clear the double negatives: $y + 6 = \frac{1}{2}(x - 6)$

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3 years ago

Which of the following inequalities matches the graph. x>-3 x<-3 y>-3 y<-3

kvv77 [185]

Answer:

Step-by-step explanation:

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3 years ago

Helppp plsssss someone D:

zimovet [89]

〽Hola User_______________

⭐Here is Your Answer..!!!

______________________

↪Cartesian Coordinates of the system....!!

↪X = rcos⊙ and Y = rsin⊙

↪since here Radius (r) = 10 units and Theta (⊙) = 225°

↪there fore substituting we get as ..

↪X = 10 ( cos 225° ) = 10 * -1/ root 2 = -7.071

↪Y = 10 ( sin 225° ) = 10 * -1/root2 = = -7.071

↪the cordinates are as follows

↪(x,y) = (-7.071, -7.071 )

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3 years ago

Raul works for the city transportation department he made a table to show the number of people that can be transported on a diff

Andru [333]

Answer:

1 : 45

Step-by-step explanation:

225 divided by 5 equals 45. You can now use this ratio to determine the number of people with different amounts of buses; when you change x from 1 to n, you would need to multiply 45 by n, and you will have your new ratio column in the table.

Hope this helps :)

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3 years ago

Read 2 more answers

A confidence interval was used to estimate the proportion of statistics students that are female. A random sample of 72 statisti

jeyben [28]

Answer:

We need a sample of size at least 13.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence interval: (0.438, 0.642).

The proportion estimate is the halfway point of these two bounds. So

$\pi = \frac{0.438 + 0.642}{2} = 0.54$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Using the information above, what size sample would be necessary if we wanted to estimate the true proportion to within ±0.08 using 95% confidence?

We need a sample of size at least n.

n is found when M = 0.08. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.08 = 1.96\sqrt{\frac{0.54*0.46}{n}}$