The amount of calories you consume after eating x

Mathematics

1 answer:

damaskus [11]3 years ago

8 0

Answer:

Domain: $x$

Number of pieces of candy: Discrete variable.

Domain of the function: $Dom\{y\} = \mathbb{N}_{O}$

Step-by-step explanation:

Let $y = 150\cdot x$ . From Function Theory, we know that domain represents the set of values of the independent function, defined by the variable $x$ in this case, whereas the range represents the set of values associated with the domain, defined by the variable $y$ in this case.

Since $x$ represents the number of pieces of candy, this variable has a discrete nature.

In addition, this linear function has a domain represented by the set of natural number and the zero element.

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This is 3 question help please

bekas [8.4K]

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3 years ago

How do you get the answer and sketch it to this graft

Katyanochek1 [597]

F(x) = -4(x - 2)² + 2
f(x) = -4((x - 2)(x - 2)) + 2
f(x) = -4(x² - 2x - 2x + 4) + 2
f(x) = -4(x² - 4x + 4) + 2
f(x) = -4(x²) + 4(4x) - 4(4) + 2
f(x) = -4x² + 16x - 16 + 2
f(x) = -4x² + 16x - 14
-4x² + 16x - 14 = 0
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x = -16 +/- √(256 - 224)
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x = -16 +/- √(32)
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x = -16 +/- 5.66
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x = -16 + 5.66 x = -16 - 5.66
 -8 -8
x = -10.34 x = -21.66
 -8 -8
x = 1.2925 x = 2.7075
f(x) = -4x² + 16x - 14
f(1.2925) = -4(1.2925)² + 16(1.2925) - 14
f(1,2925) = -4(1.67055625) + 20.68 - 14
f(1.2925) = -6.682225 + 20.68 - 14
f(1.2925) = 13.997775 - 14
f(1.2925) = -0.002225
(x, f(x)) = (1.2925, -0.002225)
or
f(x) = -4x² + 16x - 14
f(2.7075) = -4(2.7075)² + 16(2.7075) - 14
f(2.7075) = -4(7.33055625) + 43.32 - 14
f(2.7075) = -29.322225 + 43.32 - 14
f(2.7075) = 13.997775 - 14
f(2.7075) = -0.002225
(x, f(x)) = (2.7075, -0.002225)
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f(x) = 2((x - 2)(x - 2)) + 1
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f(x) = 2(x² - 4x + 4) + 1
f(x) = 2(x²) - 2(4x) + 2(4) + 1
f(x) = 2x² - 8x + 8 + 1
f(x) = 2x² - 8x + 9
2x² - 8x + 9 = 0
x = -(-8) +/- √((-8)² - 4(2)(9))
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x = 8 +/- √(64 - 72)
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x = 8 +/- √(-8)
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x = 8 +/- √(8 × (-1))
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x = 8 +/- √(8)√(-1)
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x = 8 +/- 2.83i
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x = 2 +/- 1.415i
x = 2 + 1.415i x = 2 - 1.415i
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f(2 + 1.415i) = 2(2 + 1.415i)² - 8(2 + 1.415i) + 9
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f(2 + 1.415i) = 2(4 + 2.83i + 2.83i + 2.00225i²) - 16 - 11.32i + 9
f(2 + 1.415i) = 2(4 + 5.66i + 2.00225) - 16 - 11.32i + 9
f(2 + 1.415i) = 8 + 11.32i + 4.0045 - 16 - 11.32i + 9
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or
f(x) = 2x² - 8x + 9
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f(2 - 1.415i) = 2(4 - 5.66i + 2.00225) - 16 + 11.32i + 9
f(2 - 1.415i) = 8 - 11.32i + 4.0045 - 16 + 11.32i + 9
f(2 - 1.415i) = 8 + 4.0045 - 16 + 9 - 11.32i + 11.32i
f(2 - 1.415i) = 12.0045 - 16 + 9
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f(2 - 1.415i) = 5.0045
(x, f(x)) = (2 - 1.415i, 5.0045)
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f(6) = 24 - 24
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5 0

3 years ago

Which represents a measure of volume? O 5 cm O 5 square cm 05 cm 05 cm

Elena-2011 [213]

Answer:

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