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ser-zykov [4K]
4 years ago
14

1. a^3 – 9a^3 = 2. 10x^2+10-2x+x^4= 3. (6n^4+3)+(2n^3+4)=

Mathematics
1 answer:
Citrus2011 [14]4 years ago
5 0
I don't understand the problem what are you solving for?
You might be interested in
(-y+5•3)+7.2y-9)=6.2y+n
kramer
(-y+5x3)+(7.2y-9)=6.2y+n
(-y+15)+(7.2y-9)=6.2y+n
since you're adding the two parentheses, you don't need to have them there
-y+15+7.2y-9=6.2y+n
7.2y-y +15-9 =6.2y+n
6.2y + 6 =6.2y+n
6.2y - 6.2y -n = -6
-n=-6
n=6

3 0
3 years ago
2.
Strike441 [17]

Answer:

1/3

Step-by-step explanation:

Assuming that both die are labelled 1 - 6, the successful outcomes are 3 and 5 or 3 and 6. This is 2 out of the 6 possible outcomes so the answer is 2/6 or 1/3.

8 0
4 years ago
ANSWER URGENT!!! PELAAAWJDKHFQJKW
Pavel [41]

Answer:

Step-by-step explanation:I think it 24

6 0
3 years ago
Read 2 more answers
3. Consider the following statement.
Kitty [74]

Answer:

  rarely correct

  for f(x) = 6, g(x) = 2; f(g(x)) = 6, g(f(x)) = 2 ≠ f(g(x))

Step-by-step explanation:

The order in which functions operate on each other can rarely be reversed with the same result. If the functions are inverses of each other and both have the same domain as range, then their order can be reversed.

Not so, in most other cases. An example is shown above.

4 0
4 years ago
Read 2 more answers
Find the equations of the following lines
White raven [17]

You need these two basic solutions and facts to find the equation of a line:

  • If you know the gradient m and one point (x_0,y_0):

y-y_0=m(x-x_0)

  • If you know the gradient two points (x_1,y_1),\ (x_2,y_2):

\dfrac{x-x_2}{x_1-x_2}=\dfrac{y-y_2}{y_1-y_2}

  • The slope of a line is the coefficient m when you write it in the y=mx+q form
  • Parallel lines have the same slope
  • The slopes of perpendicular lines give -1 when multiplied

We can use this list to solve all the exercises:

b)

Use the first equation to get

y-1=-4(x-2) \iff y=-4x+9

c)

Use the second equation to get

\dfrac{x-4}{2-4}=\dfrac{y-2}{-1-2} \iff \dfrac{x-4}{-2}=\dfrac{y-2}{-3}\iff 3(x-4)=2(y-2) \iff 3x-12=2y-4 \iff 2y = 3x-8 \iff y = \frac{3}{2}x-4

d) same as c)

e) We derive the slope of the line by writing it as

5y = -x-15 \iff y = -\dfrac{1}{5}x-3

So, the slope is -1/5. From here, it's the same as b)

f) same as e)

g) Again we find the slope as

3x+y+2=0\iff y=-3x-2

so the slope is -3, and a perpendicular line has slope 1/3. From there, it's the same as b).

6 0
4 years ago
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