Let f(x) = p(x)/q(x), where p and q are polynomials and reduced to lowest terms. (If p and q have a common factor, then they contribute removable discontinuities ('holes').)
Write this in cases:
(i) If deg p(x) ≤ deg q(x), then f(x) is a proper rational function, and lim(x→ ±∞) f(x) = constant.
If deg p(x) < deg q(x), then these limits equal 0, thus yielding the horizontal asymptote y = 0.
If deg p(x) = deg q(x), then these limits equal a/b, where a and b are the leading coefficients of p(x) and q(x), respectively. Hence, we have the horizontal asymptote y = a/b.
Note that there are no obliques asymptotes in this case. ------------- (ii) If deg p(x) > deg q(x), then f(x) is an improper rational function.
By long division, we can write f(x) = g(x) + r(x)/q(x), where g(x) and r(x) are polynomials and deg r(x) < deg q(x).
As in (i), note that lim(x→ ±∞) [f(x) - g(x)] = lim(x→ ±∞) r(x)/q(x) = 0. Hence, y = g(x) is an asymptote. (In particular, if deg g(x) = 1, then this is an oblique asymptote.)
This time, note that there are no horizontal asymptotes. ------------------ In summary, the degrees of p(x) and q(x) control which kind of asymptote we have.
I hope this helps!
To answer this question you will need to know how many inches the car travels Per minute.
1. To find this out you will first divide 45 miles by 60 to get the number of miles per minute.
The convertible travels 0.75 mi./min.
2. Next you will convert this number of miles to inches.
There are 63,360 inches per mile.
0.75 x 63360 = 47520 inches per minute.
3. You then need to find the distance the wheel travels in one rotation. You will need to find the circumference of the wheel.
C = pi x d
3.14 x 48
C = 150.72 inches
Each rotation is about 150.72 inches.
4. Finally, divide the total distance traveled in a minute by the circumference(distance of one rotation) to get the total number of rotations in a minute.
47520/150.72 is about 315.3 rotations per minute.
Answer:
I'm just here for my points sorry bro
Answer:
64 inches or 64 pulgadas
Step-by-step explanation:
The formula for the perimeter of a rhombus is given as:
P = 4a
Where a = side length of the rhombus
From the above question, side length of the rhombus = 16 inches
Hence, Perimeter of the rhombus = 4 × 16 inches
= 64 inches
La fórmula para el perímetro de un rombo se da como:
P = 4a
Donde a = longitud del lado del rombo
De la pregunta anterior, la longitud del lado del rombo = 16 pulgadas
Por lo tanto, perímetro del rombo = 4 × 16 pulgadas
= 64 pulgadas
