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andriy [413]
3 years ago
5

Which of the following is the factored form of the given equation?

Mathematics
2 answers:
ozzi3 years ago
5 0
6x^2 + 2x - 8 = 0
2(3x^2 + x - 4) = 0
2(3x + 4)(x - 1) = 0 <===
Marizza181 [45]3 years ago
3 0

Answer:

The correct option is 1.

Step-by-step explanation:

The given equation is

6x^2+2x-8=0

Taking out the common factor.

2(3x^2+x-4)=0

Middle term can be written as 4x-3x, to find the factored form of the given equation.

2(3x^2+4x-3x-4)=0

2(x(3x+4)-(3x+4))=0

2(3x+4)(x-1)=0

The factored form of the given equation is 2(3x+4)(x-1)=0. Therefore the correct option is 1.

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Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6
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<h2>Answer</h2>

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<h2>Explanation</h2>

Lets solve our system of equations  step by step

x^2+y^2=6 equation (1)

x^2-y=6 equation (2)

1. Solve for x^2 in equation (2)

x^2-y=6

x^2=6+y equation (3)

2. Replace equation (3) in equation (1) and solve for y

x^2+y^2=6

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3. Replace the values of y in equation (3) and solve for x

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x^2=6+y

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x=\sqrt{6} or x=-\sqrt{6}

- For y=-1

x^2=6+y

x^2=6-1

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So, the solutions of our system of equation are:

x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1

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