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andriy [413]
3 years ago
5

Which of the following is the factored form of the given equation?

Mathematics
2 answers:
ozzi3 years ago
5 0
6x^2 + 2x - 8 = 0
2(3x^2 + x - 4) = 0
2(3x + 4)(x - 1) = 0 <===
Marizza181 [45]3 years ago
3 0

Answer:

The correct option is 1.

Step-by-step explanation:

The given equation is

6x^2+2x-8=0

Taking out the common factor.

2(3x^2+x-4)=0

Middle term can be written as 4x-3x, to find the factored form of the given equation.

2(3x^2+4x-3x-4)=0

2(x(3x+4)-(3x+4))=0

2(3x+4)(x-1)=0

The factored form of the given equation is 2(3x+4)(x-1)=0. Therefore the correct option is 1.

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Darina [25.2K]

Answer:

if adding its 139 if u subtract then its 11

Step-by-step explanation:

3 0
3 years ago
Wht does ^ this mean? ​
Ainat [17]

Answer:

Concept: Analysis

  1. The carrot means an exponent.
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8 0
3 years ago
Order each set of numbers from least to greatest {7 , 9 √50, √85
Oksi-84 [34.3K]

Answer:

7,√50,9,√85

Step-by-step explanation:

The square root of 50 is 7.071 if you round to the nearest thousandth. The square root of 85 is 9.220. From least to greatest is 7,√50,9,√85

8 0
3 years ago
Which two values of x are roots of the polynomial below?
Julli [10]

Answer:

B. and C.

Step-by-step explanation:

1. Set the polynomial equal to zero:

x² + 5x + 7 = 0

2. Plug the given values of a, b, and c into the quadratic formula:

x=\frac{-5+-\sqrt{5^{2}-4(1)(7) } }{2(1)}

3. Solve the square root:

x=\frac{-5+-\sqrt{25-4(1)(7)} }{2(1)}

x=\frac{-5+-\sqrt{25-28} }{2(1)}

x=\frac{-5+-\sqrt{-3} }{2(1)}

4. Simplify the rest:

x=\frac{-5+-\sqrt{-3} }{2}

5. Separate the solutions:

x=\frac{-5+\sqrt{-3} }{2}  , x=\frac{-5-\sqrt{-3} }{2}

Thus, options B and C are the answers.

hope this helps!

4 0
2 years ago
13. In A ABC, if m BF is an angle bisector, find<br> m
Tresset [83]

If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.

Given that m∠ABF=41° and BF is an angle bisector.

We are required to find the angle m∠BCE if BF is an angle bisector.

Angle bisector basically divides an angle into two parts.

If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.

In this way ∠ABC=2*∠ABF

∠ABC=2*41

=82°

In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.

∠BCE+∠CEB+EBC=180  (Sum of all the angles in a triangle is 180°)

∠BCE+90+82=180

∠BCE=180-172

∠BCE=8°

Hence if BF is an angle bisector then angle m∠BCE=8°.

Learn more about angles at brainly.com/question/25716982

#SPJ1

4 0
1 year ago
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