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liubo4ka [24]
3 years ago
14

Given the position of 2 points of a triangle with the lengths of all side and angle of each side how can you find the 3rd positi

on of the triangle
what will be C given in x and y coordinates
ANSWER WITH A FORMULA AND NOT AN ANSWER TO THE EXAMPLE
pls don't give worng answer I really this need

EX:

A = (0,0)
B = (5,5)
C = (?,?)

AB ~= 7.07
AC = 5
BC = 5

∠A = 45
∠B = 45
∠C = 90

what formula can give C = (? , ?)
Mathematics
1 answer:
IrinaK [193]3 years ago
8 0
The answer is b:)))))))
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Helppp i will mark brainliest <3
hodyreva [135]

Answer:

59.8*4=239.2 rounded to the nearest foot is 239

Step-by-step explanation:

6 0
3 years ago
What is the slope of the line that passes through the points (9, 4)(9,4) and (3, 9)(3,9)? Write your answer in simplest form.
nalin [4]

Answer:

I’m guessing the double points is a typo.

Slope: -5/6

Step-by-step explanation:

Hope this helps <3

Btw love your username <333

6 0
2 years ago
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attashe74 [19]

Step-by-step explanation:

3 0
3 years ago
Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$
Blizzard [7]
\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}

a^{81}\equiv1^{81}\equiv1\pmod7

b^{91}\equiv2^{91}\pmod7

2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7
8\equiv1\pmod7
2\equiv2\pmod7
\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7

c^{27}\equiv6^{27}\pmod7

6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7

\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7
6 0
3 years ago
Using a linear approximation, estimate f(2.1), given that f(2) = 5 and f'(x) = √3x-1.
algol [13]

Answer:

f\left( {2.1} \right) \approx 5.22360.

Step-by-step explanation:

The linear approximation is given by the equation

                            {f\left( x \right) \approx L\left( x \right) }={ f\left( a \right) + f^\prime\left( a \right)\left( {x - a} \right).}

Linear approximation is a good way to approximate values of f(x) as long as you stay close to the point x= a, but the farther you get from x=a, the worse your approximation.

We know that,

a=2\\f(2) = 5\\f'(x) = \sqrt{3x-1}

Next, we need to plug in the known values and calculate the value of f(2.1):

{L\left( x \right) = f\left( 2 \right) + f^\prime\left( 2 \right)\left( {x - 2} \right) }=5+\sqrt{3(2)-1}(x-2) =5+\sqrt{5}(x-2)

Then

f\left( {2.1} \right) \approx 5+\sqrt{5}(2.1-2)\approx5.22360.

6 0
3 years ago
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