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cestrela7 [59]
4 years ago
14

Please answer this correctly

Mathematics
2 answers:
iogann1982 [59]4 years ago
8 0

Answer:

Hope this helps

Step-by-step explanation:

6 people did 0 sit ups

5 people did 1 sit ups

5 People did 2 sit ups

6 people did 3 sit ups

3 people did 4 sit ups

1 person did 5 sit ups

dimaraw [331]4 years ago
3 0

Answer:

Number of people

6

5

5

6

3

1

Step-by-step explanation:

All you had to do was the count how much numbers there were on the list.

Like there were 6 0s.

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What it the value of m when (2m+8)° and the other angle 24°​
alisha [4.7K]

Answer:

m = 74

Step-by-step explanation:

2m+8 +24 has to = 180 because they form a line. So the equation would be 2m+32 = 180, so then 2m would equal 148, so m = 74.

5 0
3 years ago
18(5−3w) = i need help already tryed doing it<br> pls
sesenic [268]

Answer:

90- 54w

Step-by-step explanation:

First, distribute multiply 18×5 which is 90.

Then, 18×3w which is 54 and bring the w with it.

Hope this helps :)

6 0
4 years ago
Solve f(-4) for f(x) = 7x - 4x
Strike441 [17]

Answer:

-12

Step-by-step explanation:

What you have to do is plug -4  into the function as a puzzle. So, replace all x with -4.

f(-4) = 7(-4) - 4(-4) = -28 + 16 = -12

8 0
2 years ago
I’ll make u the brainliest if right
nikdorinn [45]

Answer:

Your answer is either 2280, or 6840. Those are the only answers that make sense to me. The question is kind of confusing, because of the Math Processing Error.

Step-by-step explanation:

5 0
4 years ago
Use the limit theorem and the properties of limits to find the horizontal asymptotes of the graph of the function g(x) = x2/x2-2
ElenaW [278]

Answer:

Option b is right.

Step-by-step explanation:

A function is given as

g(x) = \frac{x^2}{x^2-2x-1}

Limit is to be found out for x tends to infinity.

We find that numerator and denominator has the same degree.

HEnce a horizontal asymptote exists

COefficients of leading terms are 1 and 1 respectively

Asymtote would be y =1/11 = 1

Alternate method:

When x tends to infinity, 1/x tends to 0

g(x) =\frac{\frac{1}{x^2} }{1-\frac{2}{x} -\frac{1}{x^2} }

by dividing both numerator and denominator by square of x.

Now take limit as 1/x tends to 0

we get

limit is y tends to 1/1 =1

Hence horizontal asymptote is y =1

8 0
4 years ago
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