substitute every x in the equation with (-2)
f(-2)=3*2*(-2) = -12
dunno if I get your equation correctly, pls check how you have written it
The values of sin (x/2) = 4/√17, cos (x/2) = 1/√17 and tan (x/2) = 4.
<h3>What is Trigonometry?</h3>
Trigonometric ratios are the ratios of the length of sides of a triangle. These ratios in trigonometry relate the ratio of sides of a right triangle to the respective angle.
Here, cos x = -15/17 (given)
we know, cos x = 2cos²x/2 - 1
cos²(x/2) = (cos x + 1)/2
cos²(x/2) = (-15/17 + 1)/2
cos²(x/2) = 1/17
cos (x/2) = 1/√17
then, sin (x/2) = √(1- cos²(x/2))
sin (x/2) = √(1 - 1/17)
sin (x/2) = √16/17
sin (x/2) = 4/√17
and tan (x/2) = sin (x/2) / cos (x/2)
tan (x/2) = 
tan (x/2) = 4
Thus, the values of sin (x/2) = 4/√17, cos (x/2) = 1/√17 and tan (x/2) = 4.
Learn more about Trigonometry from:
brainly.com/question/22698523
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answer....
Step-by-step explanation:
h
(
x
)
=
3
x
+
8
1 L = 1 dm³
1 m = 10 dm
(1 m)³ = (10 dm)³ ------> 1m³ = 1000 dm³ ------> 1m³ = 1000L
44 L *(1 m³/1000 L) = 0.044 m³
Answer is 0.044 m³.
Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a 0% probability of a sample of 50 cars recording an average speed of 66 mph or higher.
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- Mean of 62 mph, hence
. - Standard deviation of 5 mph, hence
. - Sample of 50 cards, hence

The probability of a sample of 50 cars recording an average speed of 66 mph or higher is <u>1 subtracted by the p-value of Z when X = 66</u>, hence:

By the Central Limit Theorem



has a p-value of 1.
1 - 1 = 0.
There is a 0% probability of a sample of 50 cars recording an average speed of 66 mph or higher.
A similar problem is given at brainly.com/question/24663213