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3 years ago

Enter your answers in the boxes to correctly complete this statement.

Mathematics

1 answer:

harina [27]3 years ago

3 0

Answer:

349800

Step-by-step explanation:

First Part:

The question tells you to multiply by 10 to the power of 4.

This implies that you can move the decimal point 4 numbers to the right

When you move the decimal two numbers to the right you get 3498

Then you got to move it two more numbers to the right

3498 can also be written as 3498.0000000000 (infinite amount of zeros)

So moving the decimal two more places you get 349800

Second Part:

10^4 = 10 * 10 * 10 * 10

= 10000

Count the zeros you get 4.

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2 years ago

construct a 90% confidence interval of the population proportion using the giver information x=74 n=150

FrozenT [24]

Answer:

The 90% confidence interval of the population proportion is (0.43, 0.56).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:

$CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}$

The information provided is:

<em>X</em> = 74

<em>n</em> = 150

Confidence level = 90%

Compute the value of sample proportion as follows:

$\hat p=\frac{X}{n}=\frac{74}{150}=0.493$

Compute the critical value of <em>z</em> for 90% confidence level as follows:

$z_{\alpha/2}=z_{0.10/2}=z_{0.05}=1.645$

*Use a <em>z</em>-table.

Compute the 90% confidence interval of the population proportion as follows:

$CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.493\pm 1.645\times \sqrt{\frac{0.493(1-0.493)}{150}}\\\\=0.493\pm 0.0672\\\\=(0.4258,\ 0.5602)\\\\\approx (0.43,\ 0.56)$

Thus, the 90% confidence interval of the population proportion is (0.43, 0.56).

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