We are given that Peter buys 12 bunches of bananas for 9.00.
We need to determine how much peter will pay for 8 bunches.
Let us set up proportion now.
12 bunches of bananas for 9.00 = 12 : 9
Let us assume Peter will pay for 8 bunches = $x.
Therefore, 8 bunches of bananas for x = 8 : x.
<h3>Setting up proportion:</h3><h3>

</h3>
On cross-multiplying, we get
12x = 9×8
12x = 72.
Dividing both sides by 12, we get

x=6.
<h3>Therefore, Peter will pay $6 for 8 bunches.</h3>
Answer:
It would be $465 marked up.
Step-by-step explanation:
55% of 300 is 165.
So marked up its 465 and marked down its 135.
This can be solved in two ways: With heavy tools or with just algebra.
What is your level? Have you studied calculus?
With pure algebra:
We need to find the maximum of the function <span>h = −16t^2 + 36t + 5
Lets take out -1 for simplicity:
</span><span>h = −(16t2 - 36t - 5)
For now lets just work with this: </span>16t^2 - 36t - 5
16t^2=(4t)^2
(4t-x)^2= 16t^2-2*4xt+x^2
we have -36t so x should be 4.5 as 2*4*4.5=36
Lets see what we have now:
16t^2 - 36t - 5= (4t-4.5)^2 is this true? No but close
(4t-4.5)^2= 16t^2- 2*4*4.5t +4.5^2= 16t^2-36t+20.25
16t^2 - 36t - 5 and 16t^2-36t+20.25 nearl the same just take away 25.25 from the right hand side
Getting long, just stay with me:
16t^2 - 36t - 5= (4t-4.5)^2 - 25.25
h= -{(4t-4.5)^2 -25.25}
h=-(4t-4.5)^2 + 25.25
We want to find the maximum of this function. -(4t-4.5)^2 this bit is always negative or 0, so it maximum is when it is 0. Solve: 4t-4.5=0
t=1,125
2 necklaces x $3.80 for each bead
$7.60
15.40 - 7.60
7.80
7.80 divide by 2
$3.90 for each pendant