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Alborosie
3 years ago
8

If CE= 7in. And AE=23in., AC= what?

Mathematics
1 answer:
Alecsey [184]3 years ago
8 0
 AE-CE=AC (23-7=16) (Assuming fragment AE is intersected only by C)
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Answer is: B

Step-by-step explanation: correct answer is B

b  

2

−a  

2

 

Given, acotθ+bcscθ=p

           bcotθ+acscθ=q

⇒p  

2

−q  

2

=(p−q)(p+q)

                   =[acotθ+bcscθ−bcotθ−acscθ][acotθ+bcscθ+bcotθ+acscθ]

                   =[cotθ(a−b)−cscθ(a−b)][cotθ(a+b)+cscθ(a+b)]

                   =(a−b)(cotθ−cscθ)(a+b)(cotθ+cscθ)

                   =(a  

2

−b  

2

)(cot  

2

θ−csc  

2

θ)

                   =(−1)(a  

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)[∵csc  

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                   =(b  

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)

7 0
3 years ago
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