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Sav [38]
3 years ago
14

1) how many significant digits are there in the sum of 45.10 and 102.203?

Mathematics
1 answer:
Sergio039 [100]3 years ago
7 0
Oi  :)

1) There are 3 significant digits
45.10+102.203= 147.303

2)
15 Mi/h  =  22 ft/s

3)
C= 72*m* \frac{3}{4} \\  \\ C= 72*81* \frac{3}{4} \\  \\ C= \frac{17496}{4}  \\  \\ C=4374

4)
There are 4 significant digitis. Leter C 
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