If Acot theta + Bcot theta =4 and
1 answer:
Answer is: B
Step-by-step explanation: correct answer is B
b
2
−a
2
Given, acotθ+bcscθ=p
bcotθ+acscθ=q
⇒p
2
−q
2
=(p−q)(p+q)
=[acotθ+bcscθ−bcotθ−acscθ][acotθ+bcscθ+bcotθ+acscθ]
=[cotθ(a−b)−cscθ(a−b)][cotθ(a+b)+cscθ(a+b)]
=(a−b)(cotθ−cscθ)(a+b)(cotθ+cscθ)
=(a
2
−b
2
)(cot
2
θ−csc
2
θ)
=(−1)(a
2
−b
2
)[∵csc
2
θ−cot
2
θ=1]
=(b
2
−a
2
)
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Step-by-step explanation:
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![ln(1.485)=ln[e^{0.033t}]](https://tex.z-dn.net/?f=ln%281.485%29%3Dln%5Be%5E%7B0.033t%7D%5D)

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Answer:
d
Step-by-step explanation:
Just look for the one that have right adding
Answer:
A
C
B
D
D
You're welcome
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