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Nadusha1986 [10]
3 years ago
5

Can you plsss help you will get 22 points!

Mathematics
1 answer:
marta [7]3 years ago
5 0
The answer is B because if you multiply 3*3 you get 9 and if you multiply 6*2 you get 12.Then you add 9 and 12 to get 21

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Solve the equation by using the basic properties of logarithms. log(2x)=3
Scilla [17]
If no base is mentioned, asssume base 10

remember
log_a(b)=c translates toa^c=b
so
since no base mentioned, assume base 10

log_{10}(2x)=3 translates to 10^3=2x then
1000=2x
divide both sides by 2,
500=x
5 0
3 years ago
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What the answer for this<br> and no it's not 118 I just accidentally clicked on it
Levart [38]
I think it is 32

Sometimes the first option has higher chance to be correct
8 0
2 years ago
What is the absolute value transformation of this function?
xxMikexx [17]

Answer:

k(x) = -|x + 2| + 3

Step-by-step explanation:

Parent function of the absolute function given in the graph,

f(x) = |x|

1). Function 'g' is reflected across the x-axis, then the image will be,

  h(x) = -f(x) = -|x|

2). Function 'h' the shifted 2 units left and 3 units upwards, image function will be,

  k(x) = h(x + 2) + 3

  k(x) = -|x + 2| + 3

Therefore, the transformed function is k(x) = -|x + 2| + 3.

6 0
2 years ago
Work out the value of <img src="https://tex.z-dn.net/?f=2%5E%7B3%7D%20%2B%205%5E%7B2%7D" id="TexFormula1" title="2^{3} + 5^{2}"
Luden [163]

Answer:

33

Step-by-step explanation:

2³=8

5²=25

8+25=33.

so, 2³+5²=33

4 0
3 years ago
Read 2 more answers
The shark are fed three times a day during the morning feeding 2/15 of a ton. During the afternoon feeding the weight of fish fe
UNO [17]

Answer:

The shark are fed \frac16 \ ton of fish during the night.

Step-by-step explanation:

Given:

Weight of fish fed in the morning = \frac{2}{15}\ ton

Also Given:

During the afternoon feeding the weight of fish fed will be 1/15 of a ton more than the fish fed during the morning.

Weight of fish fed in the afternoon = \frac{2}{15}+\frac{1}{15}=\frac{2+1}{15}=\frac{3}{15}\ ton

Total fish fed in whole day = \frac12 \ ton

We need to find the Weight of fish fed in the night.

Solution:

Now we can say that;

Weight of fish fed in the night can be calculated by by subtracting Weight of fish fed in the morning and Weight of fish fed in the afternoon from Total fish fed in whole day .

framing in equation form we get;

Weight of fish fed in the night = \frac{1}{2}-\frac{2}{15}-\frac{3}{15}= \frac{1}{2}-(\frac{2}{15}+\frac{3}{15})=\frac{1}{2}-\frac{2+3}{15}= \frac{1}{2}-\frac{5}{15} = \frac{1}{2}-\frac{1}{3}

Now we will use LCM for making the denominator common we get;

Weight of fish fed in the night = \frac{1\times3}{2\times3}-\frac{1\times2}{3\times2} = \frac{3}{6}-\frac{2}{6}

Now denominator are common so we will solve the numerators.

Weight of fish fed in the night = \frac{3-2}{6}=\frac16 \ ton

Hence The shark are fed \frac16 \ ton of fish during the night.

3 0
2 years ago
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