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2 years ago

Twice the difference of a number and 16 is the same as three times a number less than 18

Mathematics

1 answer:

Maksim231197 [3]2 years ago

4 0

Answer:

Step-by-step explanation:

Let x be the "number."

"twice the difference of a number and 16" can be written as:

2(x-16)

"is the same as three times a number less than 18" can be written as:

= 3(x<18)

I wonder if this was meant to say "is the same as three times a number less 18," instead of "less than 18." If so, we would have:

=3(x-18)

1. Using the sentence as written: 2(x-16) = 3(x<18)

2. Using the sentence as amended: 2(x-16) = =3(x-18)

Going with this interpretation:

2(x-16) = 3(x-18)

2x - 32 = 3x - 54

x = 22

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Three siblings collect rare coins. Howany rare coins does each sibling have if theyhave a total of 49 rare coins?

Dafna1 [17]

49 divided by 3 = 16.33
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3 years ago

Fifty three less than twuce a number is 31 what is the number

BartSMP [9]

Answer:

Step-by-step explanation:

So if the result of it is 31,

And it is 53 less you would add back 53

53 + 31 = 84

And it is twice a number so you divide by 2 (opposite of twice a number)

84/2 = 42

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3 years ago

What is three times as long of 20 square meters

Stolb23 [73]

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3 years ago

The average cost of tuition, room and board at small private liberal arts colleges is reported to be $8,500 per term with a stan

Svetlanka [38]

Answer:

z=3.8196

Step-by-step explanation:

-We notice that this is a normal distribution problem.

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$z=\frac{x-\mu_o}{\sigma/\sqrt{n}}\\\\=\frac{8745-8500}{1200\sqrt{350}}\\\\\\=3.8196$

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3 0

3 years ago

Jack likes to go fishing. While waiting for the fishes to bite, he formulates the following model for the process: fishes bite a

gogolik [260]

Answer:

a) 0.122

b) 3.35 × 10⁻⁴

c) 0.1071

Step-by-step explanation:

Here we have the Poisson process given by

$P(N(t) = k) = \frac{e^{-\lambda t} (\lambda t)^k }{k!}$

Where:

λ = Rate = 4 bites/hour and

t = Length of time that is

Mean = λt

Where k = 6 fishes bites and t = 2 hours we have

$P(N(2) = 6) = \frac{e^{-4 \times 2} (4 \times 2)^6 }{6!} = 0.122$

b) The probability that he fails to catch any fishes during the first two hours is the probability t that he catches 0 fish as follows

$P(N(2) = 0) = \frac{e^{-4 \times 2} (4 \times 2)^0 }{0!} = 3.35 \times 10^{-4}$

$P(N(2) = 6) = 0.122$

For 1 fish caught in two times we have first time no fish and second time he caches a fish gives

0.122×(1-0.122) = 0.1071

4 0

3 years ago