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stellarik [79]
3 years ago
15

Twice the difference of a number and 16 is the same as three times a number less than 18

Mathematics
1 answer:
Maksim231197 [3]3 years ago
4 0

Answer:

Step-by-step explanation:

Let x be the "number."

"twice the difference of a number and 16" can be written as:  

2(x-16)

"is the same as three times a number less than 18" can be written as:

= 3(x<18)

I wonder if this was meant to say "is the same as three times a number less  18," instead of "less than 18."  If so, we would have:

=3(x-18)

1.  Using the sentence as written:  2(x-16) = 3(x<18)

2.  Using the sentence as amended:  2(x-16) = =3(x-18)

 Going with this interpretation:  

 2(x-16) = 3(x-18)

2x - 32 = 3x - 54

x = 22

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2) Line segment MK has endpoints at (2, 3) and (5, ?4). Segment M'K' is the reflection of MK over the y-axis. Which statement de
Marianna [84]

Answer:

Option C -M'K' is the same length as MK

Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

               M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let (x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

⇒ d=\sqrt{(2-5)^2+(4-3)^2}

⇒d=\sqrt{9+1}

⇒d=\sqrt{10}   ....(1)

Now, we find the length of M'K'

let (x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)

d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}

⇒ d^{'}=\sqrt{(-2+5)^2+(3-4)^2}

⇒d^{'}=\sqrt{9+1}

⇒d^{'}=\sqrt{10} .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct


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