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2 years ago

Help? I dontn understand this! algreba is weird and hard

Mathematics

1 answer:

Softa [21]2 years ago

5 0

1. B
2.0.9925
3.C
4.A
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2 years ago

Fill in the missing information. Tim Worker is doing his budget. He discovers that the average miscellaneous expense is $45.00 w

nlexa [21]

Answer:

$P(38.6$

And we can assume a normal distribution and then we can solve the problem with the z score formula given by:

$z=\frac{X -\mu}{\sigma}$

And replacing we got:

$z=\frac{38.6- 45}{16}= -0.4$

$z=\frac{57.8- 45}{16}= 0.8$

We can find the probability of interest using the normal standard table and with the following difference:

$P(-0.4$

Step-by-step explanation:

Let X the random variable who represent the expense and we assume the following parameters:

$\mu = 45, \sigma 16$

And for this case we want to find the percent of his expense between 38.6 and 57.8 so we want this probability:

$P(38.6$

And we can assume a normal distribution and then we can solve the problem with the z score formula given by:

$z=\frac{X -\mu}{\sigma}$

And replacing we got:

$z=\frac{38.6- 45}{16}= -0.4$

$z=\frac{57.8- 45}{16}= 0.8$

We can find the probability of interest using the normal standard table and with the following difference:

$P(-0.4$

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3 years ago

If equation two is multiplied by -2 and then the equations are added, the result is

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Answer: Yes, this is true but it can be a different answer.

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2 years ago

How high did Abby climb above their original starting<br> position?

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Idk what are the possible answers

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2 years ago

Read 2 more answers

Lim (sin x )^tanx as x->pi/2

Sholpan [36]

<span>lim (x → π/2) (sinx)^(tanx)
= lim (x → π/2) e^[(tanx) ln (sinx)]
= e^ [lim (x → π/2) (tanx) ln (sinx)] ... (1)

lim (x → π/2) (tanx) ln (sinx)
= lim (x → π/2) [ln(sinx) / cotx]

Using L'Hospital'stheorem,
= lim (x → π/2) [- cotx / cosec^2 x]
= 0

Plugging in ( 1 ),
required limit = e^0 = 1

=>Answer is 1.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>

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3 years ago