Answer:
100
Step-by-step explanation:
We have the sum of first n terms of an AP,
Sn = n/2 [2a+(n−1)d]
Given,
36= 6/2 [2a+(6−1)d]
12=2a+5d ---------(1)
256= 16/2 [2a+(16−1)d]
32=2a+15d ---------(2)
Subtracting, (1) from (2)
32−12=2a+15d−(2a+5d)
20=10d ⟹d=2
Substituting for d in (1),
12=2a+5(2)=2(a+5)
6=a+5 ⟹a=1
∴ The sum of first 10 terms of an AP,
S10 = 10/2 [2(1)+(10−1)2]
S10 =5[2+18]
S10 =100
This is the sum of the first 10 terms.
Hope it will help.
Answer:
Diagram for success. ...
Know your properties and theorems. ...
Understand Euclid's postulates. ...
Learn the language of math. ...
Know your angles. ...
Know your triangles. ...
Figure out what you want and what you're given. ...
Now fill in the rest.
Step-by-step explanation:
I need a picture of the figure so I can calculate it.
Answer:
Help with what... there is no question