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taurus [48]
3 years ago
7

Simplify the expression c^-6 * d^4/ c^-16 * d^14​

Mathematics
1 answer:
Naily [24]3 years ago
7 0

Answer:

\dfrac{c^{10}}{d^{10}}

Step-by-step explanation:

Although the way you wrote problem, this is not what it looks like, I think this is what you meant.

\dfrac{c^{-6} \times d^{4}}{c^{-16} \times d^{14}} =

= \dfrac{c^{-6}}{c^{-16}} \times \dfrac{d^{4}}{d^{14}}

= c^{-6 - (-16)} \times d^{4 - 14}

= c^{-6 + 16} \times d^{-10}

= c^{10} \times d^{-10}

= \dfrac{c^{10}}{d^{10}}

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4-[(x+3)/ ((x^2 +5x +6)/(x-2))]
Vinil7 [7]

Answer:

3 + 4/(x+2)

Step-by-step explanation:

4-[(x+3)/ ((x^2 +5x +6)/(x-2))]=

4- [(x+3)*(x-2)/(x^2 +5x +6))]=

4- [(x+3)(x-2)/(x+3)(x+2)]=

4-(x-2)/(x+2)=

(4x+8-x+2)/(x+2)=

(3x+10)/(x+2)=

3 + 4/(x+2)

4 0
3 years ago
A motorboat takes
vagabundo [1.1K]
Recall your d = rt, distance = rate * time

let's say the boat's rate is "b" in still water, and the current's rate is "c"

as the boat goes upstream, is not really going "b" fast, the water is not still anyway, is going much slower, is going " b - c ", because the current's rate is eroding speed because is going against the current.

as the boat goes downstream, is not going "b" fast either, is going faster, is going " b + c " fast, because is going downstream and thus with the current and the current is adding speed to it.  notice, it takes longer going up, 5hrs, then coming down, 3hrs, same 150 on each way.

\bf \begin{array}{llll}
&distance&rate&time\\
&-----&-----&-----\\
upstream&150&b-r&5\\
downstream&150&b+r&3
\end{array}
\\\\\\

\begin{cases}
150=(b-r)5\\
\qquad \frac{150}{5}=b-r\\
\qquad 30=b-r\\
\qquad 30+r=\boxed{b}\\
150=(b+r)3\\
\qquad \frac{150}{3}=b+r\\
\qquad 50=b+r\\
\qquad 50=\boxed{30+r}+r
\end{cases}

solve for "r"

what's the boat's rate? well, 30+r = b
4 0
3 years ago
The graph of f(x) = xx is reflected across the x-axis and then across the y-axis to create the graph of function g(x).
V125BC [204]

Now let's examine the statements:

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B)The functions have the same domains. FALSE the doman changed from x ≥ 0 to x ≤ 0

C)The only value that is in the domains of both functions is 0. TRUE: the intersection of x ≥ 0 with x ≤ 0 is 0.

D)There are no values that are in the ranges of both functions. FALSE: 0 is in the ranges of both functions.

E)The domain of g(x) is all values greater than or equal to 0. FALSE: it was proved that the domain of g(x) is all values less than or equal to 0.

F)The range of g(x) is all values less than or equal to 0. TRUE: it was proved above.

3 0
3 years ago
Read 2 more answers
Show your work: convert 1/8 into a decimal
lukranit [14]

answer : 0.125

explanation: it’s actually really easy all you have to do is

take the fraction and divide it like :

1/8 = 1 divided by 8 = 0.125
3 0
3 years ago
If the volume of sand is increasing at a constant rate, is the height increasing at a constant rate? Explain.
AysviL [449]
It does not necessarily mean that the height will rise although I it could rise.this is because volume is what is inside your shape. It could spread out more and have more volume. If you think I'm smart let me tell you I'm only in 4th grade not bragging
4 0
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