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3 years ago

Write the quadratic equation whose roots are 5 and -3, and whose leading coefficient is 1

1 answer:

4 0

1. A quadratic equation has the following form: ax²+bx+c.

2. The leading coefficient is the number that is attached to the variable with the highest exponent. Then, the "a" is the leading coefficient of the quadratic equation.

3. The problem says that the leading coefficient is 1 (a=1) and the roots of the quadratic equation are 5 and -3. Then, you have:

(x-5)(x+3)=0

4. When you apply the distributive property, you obtain:

x²+3x-5x-15=0
x²-2x-15=0

5. Therefore, the answer is:

x²-2x-15=0

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Y +

Usimov [2.4K]

Question:

What is the common denominator of $y+\frac{y-3}{3}$ in the complex fraction $\frac{y+\frac{y-3}{3}}{\frac{5}{y}+\frac{2}{3 y}}$

A) $3 y(y-3)$

B) $y(y-3)$

C) $3y$

D) $3$

Answer:

Option D : 3 is the common denominator

Explanation:

It is given that the complex fraction $\frac{y+\frac{y-3}{3}}{\frac{5}{y}+\frac{2}{3 y}}$

We need to determine the common denominator of $y+\frac{y-3}{3}$ from the complex fraction.

Let us consider the fraction $y+\frac{y-3}{3}$

To find the common denominator, let us take LCM.

Thus, rewriting the above fraction as,

$\frac{y}{1} +\frac{y-3}{3}$$

The LCM can be determined by multiplying the denominators.

Thus, we get,

$1\times3=3$

Thus, the common denominator is 3.

Hence, Option D is the correct answer.

6 0

3 years ago

I am supposed to model this question with a inequality equation. Could someone please show me how I would write the equation?

lesya [120]

Scavdfdscdeereedefrrdeeeeeqwwwwwwwwwwwrrtrrrrrresfr

4 0

3 years ago

Find QS 7 22 19 6 none are correct

notsponge [240]

Answer:

-10

Step-by-step explanation:

None of the above

8 0

2 years ago

Read 2 more answers

I need help solving this

Alekssandra [29.7K]

Answer:

I'd say x is 15-16

it's only a bit larger than the 10

4 0

2 years ago

eight ears of corn and a cantaloupe cost $2.37. six ears of corn and 3 cantaloupes cost $3.51. what does a cantaloupe cost?

abruzzese [7]

In the given question, there are two vital information's give. Firstly 8 ears of corn and 1 cantaloupe cost $2.37. On the other hand 6 ears of corn and 3 cantaloupes cost $3.51.
Let us assume the cost of 1 corn = X
Let us assume the cost of 1 cantaloupe = Y
Then
8X + Y = 2.37
Y = 2.37 - 8X
And
6X + 3Y = 3.51
Now we replace the value of Y we found from the first equation
Then
6X + 3(2.37 - 8X) = 3.51
6X - 24X + 7.11 = 3.51
-18X = 3.51 - 7.11
-18X = -3.6
X = 3.6/18
   = 0.20
So $0.20 is the value of 1 corn. Then the value of a cantaloupe
Y = 2.37 - 8X
   = 2.37 - (8 * 0.20)
   = 2.37 - 1.6
   = 0.77
So cost of a cantaloupe is $0.77

3 0

3 years ago