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Amiraneli [1.4K]
3 years ago
6

Write the quadratic equation whose roots are 5 and -3, and whose leading coefficient is 1

Mathematics
1 answer:
kogti [31]3 years ago
4 0
1. A quadratic equation has the following form: ax²+bx+c.
 
 2. The leading coefficient is the number that is attached to the variable with the highest exponent. Then, the "a" is the leading coefficient of the quadratic equation.
 
 3. The problem says that the leading coefficient is 1 (a=1) and the roots of the quadratic equation are 5 and -3. Then, you have:
 
 (x-5)(x+3)=0
 
 4. When you apply the distributive property, you obtain:
 
 x²+3x-5x-15=0
 x²-2x-15=0
 
 5. Therefore, the answer is:
 
 x²-2x-15=0
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The sum of two numbers is
bekas [8.4K]
Okay you have 2 sum unknow lets call them X+Y

so X+Y=33, 4X=108

Get X by it self then plug it in 4X=108

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Read 2 more answers
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3 0
3 years ago
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defon
We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

x= \frac{-b+- \sqrt{ b^{2}-4ac } }{2a}

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a = coefficient of squared term = 1
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Using the values, we get:

x= \frac{-5+- \sqrt{25-4(1)(7)} }{2(1)} \\  \\ &#10;x= \frac{-5+- \sqrt{-3} }{2}

So, the correct answer to this question are option E and F
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3 years ago
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