In the graph, line AB is parallel to line CD. Graph the image of the lines after a 90° counterclockwise rotation about the origi
n.
1 answer:
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Answer:
(a) By cosine rule, /PQ/2=202+152−2×20×15×cos145°
= 400+225−600cos145°
= 625+600×0.8192
= 491.52+625
/PQ/2=1116.52⟹/PQ/=1116.52−−−−−−√=33.41
≊33km ( to the nearest whole number)
(b) By sine rule,
sin<QPR15=sin14533.41
sin<QPR=15sin14533.41
sin<QPR=15×0.573633.41=0.2575
<QPR=14.92°
∴ Bearing of Q from P = 25° + 14.92° = 39.92°.
≊40° (to nearest whole number)
Step-by-step explanation:
hope it helps
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