If a solution(s) exists y=y so we can say:
x^2-3x=-2x+2 add 2x to both sides
x^2-x=2 subtract 2 from both sides
x^2-x-2=0 factor
(x-2)(x+1)=0
So x=-1 and 2, using y=-2x+2 we find:
y(-1)=4 and y(2)=-2
So the two solutions occur at the points:
(-1,4) and (2,-2)
The distance between two points knowing theirs coordinates:
AB =√[(x₂-x₁)² +(y₂-y₁)²]; ===>A(-2,4) & B(0,-6) Given
A(x₁,y₁) & B(y₂,y₁)
AB =√[(0-(-2))²+(-6-4)²] =√(104) = 10.198 ≈ 10.2
Answer: 6.40 = c
Step-by-step explanation:
a^2 + b^2 = c^2
5^2 + 4^2 = c^2
25 + 16 = c^2
41 = c^2
____
_/ 41 = c
6.40 = c
divide food money by income:
468 /2600 = 0.18 = 18%
