Given
A rectangular park of length 60 m breadth 50 m encloses with volleyball court of length 18 m and breadth 10 m.
To find:
The area of the park excluding the court at the rate of Rs 110 per square meter.
Solution:
Area of a rectangle is:
Area of whole park is:
Area of volleyball court is:
Now, the area of the park excluding the court is:
Therefore, the area of the park excluding the court is 2820 square meter.
Step-by-step explanation:
remember. the radius is always half the diameter.
volume of a cylinder
pi × r² × height
pi×7.5²×48 = pi×56.25×48 = 8,482.300165... in³
volume of a sphere
4/3 × pi × r³
and that volume should be the same as the cylinder. so,
4/3 × pi × r³ = pi×56.25×48
4/3 × r³ = 56.25 × 48
1/3 × r³ = 56.25 × 12
r³ = 56.25 × 36 = 7.5² × 6² = (7.5×6)² = 45² = 2025
![r = \sqrt[3]{2025}](https://tex.z-dn.net/?f=r%20%3D%20%20%5Csqrt%5B3%5D%7B2025%7D%20)
which would be 12.65148998... in.
Answer:
<em>Would be the answer D(1, −4) </em>
Step-by-step explanation:
<em>Excuse me if i'm wrong, it seems like you have the same test or almost. And this was the answer on mine. I hope it works out for you!</em>
Answer:
He can spend $118.50 each day
Step-by-step explanation:
1000 - 348.25 = 651.75
651.75 / 5.5 = 118.5
Answer:
d = 1 7/24 or 31/24; midpoint would be half of that,or 31/48
Step-by-step explanation:
Since distance is absolute value, add 2/3 and 5/8 to get the entire distance. Midpoint is that distance divided by 2.
