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3 years ago

The temperature is -2c. If the temperature rises by 15c what is the new temperature?

Mathematics

2 answers:

gtnhenbr [62]3 years ago

7 0

Answer:

13c

Step-by-step explanation:

To find the new temperature, add 15 to -2, since the temperature rose by 15c and was originally -2c.

-2 + 15

= 13

So, the new temperature will be 13c.

svetoff [14.1K]3 years ago

3 0

Answer:

13c

Step-by-step explanation:

-2+15=13

13c

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The sum of two numbers is less than 2. If we subtract the second number from the first, the difference is greater than 1. What a

Anna007 [38]

Answer:

the value of these two numbers are 1/2 and 3/2

Step-by-step explanation:

Given that:

x+y < 2 ---- (1)

y - x > 1 ---- (2)

From equation (2), let y > 1 + x then substitute it into equation (1)

x + 1 + x < 2

2x + 1 < 2

2x < 2 - 1

2x < 1

x < 1/2

From equation (2), replace the value of x to be 1/2

y - 1/2 > 1

y > 1 + 1/2

y > 3/2

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3 years ago

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3 years ago

What is 9% of 31? Do not round, write the exact amount

Artyom0805 [142]

Answer:

2.79

Step-by-step explanation:

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3 years ago

Read 2 more answers

If p is the incenter of triangle jkl, find each measure

Hunter-Best [27]

Answer:

PO = 7

PM = 7

MJ = 11

∠PJO = 32°

∠KJL = 64°

PL ≈ 18.385

OL = 17

∠PLO = 22°

∠NLO = 44°

∠JKL = 72°

∠MKP = 36°

∠NKP = 36°

∠PKN = 36°

KN = 10

PL ≈ 13.04

PK ≈ 12.21

JL = 28

JK = 21

LK = 27

Step-by-step explanation:

The given parameters are;

The point representing the incenter of the triangle = P

Therefore PO = PM = PN = 7

tan(32°) = PM/JM = 7/JM

∴JM = 7/(tan(32°)) ≈ 11.2

∠PJO = tan⁻¹(7/11)≈ 32.47°

∠PJO = ∠PJM = 32° similar triangles

∠KJL = ∠KJP + ∠PJO = 32 + 32 = 64°

∠KJL ≈ 64°

PL = √(7² + 17²) ≈ 18.385

OL = NL = 17 similar triangles

∠PLO = sin⁻¹(7/18.385) ≈ 22.380°

∠PLO = ∠PLN = 22°

∠NLO = ∠PNL + ∠OLP ≈ 22° + 22° ≈ 44°

∠NLO ≈ 44.380°

∠JKL = 180 - (∠KJL + ∠NLO)

∠JKL = 180° - (64° + 44°) ≈ 72°

∠JKL ≈ 72°

∠MKP = ∠NKP = 72°/2 = 36°

∠MKP = 36°

∠NKP = 36°

∠PKN = ∠JKL - ∠MKP = 72° - 36° ≈ 36°

∠PKN ≈ 36°

KN = KM = 10

MJ = OJ = 11

PL = √(7² + 11²) ≈ 13.04

PK = √(7² + 10²) ≈ 12.21

JL = JO + OL = 11 + 17 = 28

JK = JM + MK = 11 + 10 = 21

LK = LN + NK = 17 + 10 = 27

6 0

3 years ago

In a basketball game, a regular basket is worth 2 points and a long distance basket is worth 3 points. There were 54 baskets in

Alla [95]

Answer:

The system of equations for the given situation is:

$x+y=54$

$2x+3y=118$

Step-by-step explanation:

Given:

Regular basket is worth = 2 points

Long distance basket is worth =3 points

Total baskets in a game = 54

Total points in total = 118

$x\rightarrow$ represents the number of regular baskets

$y\rightarrow$ represents the number of long distance baskets.

Expression for total baskets can be given by ⇒ $x+y$

Thus first equation representing total baskets in a game is given by:

$x+y=54$

Since a regular basket is worth 2 points

So $x$ regular baskets would be worth $=2x$ points

Since a long distance basket is worth 3 points

So $y$ long distance baskets would be worth $=3y$ points

Expression for total points in a game can be given by ⇒ $2x+3y$

Thus second equation representing total points in a game is given by:

$2x+3y=118$

∴ The system of equations for the given situation is:

$x+y=54$

$2x+3y=118$

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3 years ago