3 years ago

Find the slope of the line that passes through the points (-8, -3) and (2, 3)

Mathematics

2 answers:

leva [86]3 years ago

6 0

Answer:

3/5

Step-by-step explanation:

3/5 is the slope passing through (-8,-3) and (2,3). use slope formula m=y^2-y^1/x^2-x^1

kherson [118]3 years ago

4 0

Answer:

The slope is 3/5.

Step-by-step explanation:

Slope formula:

$\displaystyle \frac{y_2-y_1}{x_2-x_1}=\frac{rise}{run}$

$\displaystyle \frac{3-(-3)}{2-(-8)}=\frac{6}{10}=\frac{6\div2}{10\div2}=\frac{3}{5}$

Therefore, the slope is 3/5, and the correct answer is 3/5.

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The area of the region in the first quadrant between the graph of y = k*sin(x) and x-axis (where k > 0 ) on the closed interv

astraxan [27]

Note that $0\le k\sin x\le k$ in the given closed interval, so the area is exactly given by the definite integral

$\displaystyle\int_0^\pi k\sin x\,\mathrm dx$

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Integrating gives

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