What does the small number 2 show in this chemical formula H20?

Naddik [55]

The middle number is 0 and the last is -81Factoring means we want something like(b+_)(b+_)We need two numbers that add together to get and Multiply to get -81which are 9 and -9:9+-9 = 0 and 9*-9 = -81
Fill in the blanks in
(b+_)(b+_)
with 9 and -9 to get...(b+9)(b−9)
The answer is : (b+9)(b−9)

7 0

2 years ago

urn I contains 1 red chip and 2 white chips; urn II contains 2 red chipsand 1 white chip. One chip is drawn at random from urn I

vitfil [10]

Answer:

Following are the answer to this question:

Step-by-step explanation:

In the question first calls the W if the transmitted chip was white so, the W' transmitted the chip is red or R if the red chip is picked by the urn II.

whenever a red chip is chosen from urn II, then the probability to transmitters the chip in white is:

$P(\frac{w}{R}) = \frac{P(W\cap R)}{P(R)} \ \ \ \ \ _{Where}\\\\P(R) = P(W\cap R) + P(W'\cap R) \\$

The probability that only the transmitted chip is white is therefore $P(W) = \frac{2}{3}\\$ , since urn, I comprise 3 chips and 2 chips are white.

But if the chip is white so, it is possible that urn II has 4 chips and 2 of them will be red since urn II and 2 are now visible, and it is possible to be: $P(\frac{R}{W}) = \frac{2}{3}$

$P(W\cap R) = P(W) \times P(\frac{R}{W}) \\$

$= \frac{2}{3}\times \frac{2}{4} \\\\= \frac{2}{3}\times \frac{1}{2} \\\\= \frac{2}{3}\times \frac{1}{1} \\\\=\frac{1}{3}\\\\= 0.333$

Likewise, the chip transmitted is presumably red $(P(W')= \frac{1}{3})$ and the chip transferred is a red chip of urn II $(P(\frac{R}{W'})= \frac{3}{4}$ , and a red chip is likely to be red $(\frac{R}{W'})$ .

Finally, $P(W'\cap R) = P(W') \times P(\frac{R}{W'})\\$

$= \frac{1}{3} \times \frac{3}{4} \\\\ = \frac{1}{1} \times \frac{1}{4} \\\\=\frac{1}{4}\\\\= 0.25$

The estimation of $P(R)$ and $P(\frac{W }{R})$ as:

$P(R) = 0.3333 + 0.25\\\\ \ \ \ \ \ \ \ \ \ = 0.5833 \\\\ P(\frac{W}{R}) = \frac{0.3333}{0.5833} \\\\\ \ \ \ \ \ \ = 0.5714$

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=T%3D2%5Cpi%20%5Csqrt%7Bl%2Fg%7D" id="TexFormula1" title="T=2\pi \sqrt{l/g}" alt="T=2\pi \sqrt{

Ket [755]

Answer:

T^2*g / 4pi^2 = l

Step-by-step explanation:

T = 2 * pi * sqrt( l/g)

We need to solve for l

Divide each side by 2pi

T/ (2pi) = 2 * pi/2pi * sqrt( l/g)

T/ (2pi) = sqrt( l/g)

Now square each side

(T/ (2pi))^2 = ( sqrt( l/g))^2

T^2 / 4pi^2 = l/g

Multiply each side by g

T^2 / 4pi^2 * g= l/g*g

T^2*g / 4pi^2 = l

8 0

2 years ago

The question is th picture

Ganezh [65]

Answer:

-6/3x

Step-by-step explanation:

gradient = slope

Rise/run = -6/3x

7 0

2 years ago

An organization is contemplating the implementation of a drug test as part of screening potential employees. The drug test is no

Leviafan [203]

Answer:

(c) A false negative (concluding the job candidate is not a drug user when he or she indeed is)

Step-by-step explanation:

First, we need to determine if it is possible for type II error to occur or not.

In analysis, type 2 error occurs when the stated null hypothesis is false.

The given null hypothesis here is "a job candidate is not a drug user" which indicates false. This means that option (e) cannot be the solution.

Having established that there is a possibility for an occurrence of type II error.

Next, is to determine the error.

Type II error implies false negative; hence, options (a), (b) and (d) cannot be the solution.

(c) is correct.

5 0

2 years ago