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3 years ago

I DONT UNDERSTAND WHICH WAY THESE SHOULD GO. Please someone explainnnnnn

Mathematics

1 answer:

uranmaximum [27]3 years ago

6 0

I believe your answer is A.) ASA

ASA stands for angle-side-angle, meaning you need an angle then an adjacent side then another adjacent angle to be congruent to say that these are congruent triangles. Because the semi circles represent congruent angles, they share a side (making them congruent) and both have corresponding right angle measures (making them congruent), you can say that these two triangles are congruent by ASA.

Hope this made sense!

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Check all subsets the number belongs to:

Shkiper50 [21]

Answer:

integer natural and whole

Step-by-step explanation:

well oviously a integer because its a number and a natural i beleve because its not owned by any brakets such as a divide a multiply or a negitive so its naturalcand whole because ist a whole number and not split with fractions

8 0

3 years ago

Given: △ABC, BC>AC, D∈ AC , CD=CB Prove: m∠ABD is acute

Aleksandr [31]

Answer:

Step-by-step explanation:

Given: △ABC, BC>AC, D∈ AC , CD=CB

To prove: m∠ABD is acute

Proof: In ΔABC, the angle opposite to side BC is ∠BAC and the angle opposite to side AC is ∠ABC.

Now, it is given that BC>AC, then ∠BAC>∠ABC.. (1)

In ΔBDC, using the exterior angle property,

∠ADB=∠DBC+∠BCD

∠ADB=∠DBC+∠BCA

⇒∠ADB>∠BAC (2)

From equation (1) and (2), we get

∠ADB>∠BAC

⇒∠ADB>∠ABC

⇒DB>AB

Hence, m∠ABD is acute

4 0

3 years ago

Can somebody find x.

serg [7]

To find X you use the equation
a*2+c*2=b*2
18*2+c*2=22*2
324+c=484
484-324=160
and then /---
160 is the answer

5 0

2 years ago

Himari gave birth to twins and named them Adrian and Chang. When they were first born, Adrian massed 2.87 kilograms and was 54.5

Likurg_2 [28]

Answer:

The babies massed in total 7.41 kg

Step-by-step explanation:

we know that

To find out the total mass, sum Adrian's mass and Chang's mass

The total mass is equal to

$2.87+4.54=7.41\ kg$

therefore

The babies massed in total 7.41 kg

4 0

3 years ago

Read 2 more answers

F(x, y, z) = yzexzi + exzj + xyexzk,

Ghella [55]

$\nabla f(x,y,z)=\mathbf F(x,y,z)\iff\dfrac{\partial f}{\partial x}\,\mathbf i+\dfrac{\partial f}{\partial y}\,\mathbf j+\dfrac{\partial f}{\partial z}\,\mathbf k=yze^{xz}\,\mathbf i+e^{xz}\,\mathbf j+xye^{xz}\,\mathbf k$

$\dfrac{\partial f}{\partial x}=yze^{xz}$
$\implies f(x,y,z)=\dfrac{yz}ze^{xz}+g(y,z)=ye^{xz}+g(y,z)$

$\dfrac{\partial f}{\partial y}=e^{xz}=e^{xz}+\dfrac{\partial g}{\partial y}$
$\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)$

$\dfrac{\partial f}{\partial z}=xye^{xz}=xye^{xz}+\dfrac{\mathrm dh}{\mathrm dz}$
$\implies\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=C$

$f(x,y,z)=ye^{xz}+C$

$\mathbf r(t)=(t^2+5)\,\mathbf i+(t^2-1)\,\mathbf j+(t^2-5)\,\mathbf k$
$\implies\mathbf r(0)=5\,\mathbf i-\mathbf j-5\,\mathbf k$
$\implies\mathbf r(5)=30\,\mathbf i+24\,\mathbf j+20\,\mathbf k$

By the gradient theorem, we have for any path $\mathcal C$ originating at the point (5, -1, -5) and terminating at the point (30, 24, 20),

$\displaystyle\int_{\mathcal C}\mathbf F\cdot\mathrm d\mathbf r=f(\mathbf r(5))-f(\mathbf r(0))=f(30,24,20)-f(5,-1,-5)$
$\implies\displaystyle\int_{\mathcal C}\mathbf F\cdot\mathrm d\mathbf r=24e^{600}+e^{-25}$

4 0

2 years ago