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NeX [460]
3 years ago
12

In triangle ABC, AB=c, BC=a, CA=b

Mathematics
1 answer:
quester [9]3 years ago
7 0

Answer:

Step-by-step explanation:

Correct option is

B

AE  

2

=  

9

73

​  

 

C

tanθ=  

8

3

​  

 

Hence

BD=DE=EC=  

3

5

​  

 and △ABC is a right angled triangle.

Now  

cosC=  

2.AC.EC

AC  

2

+EC  

2

−AE  

2

 

​  

 

Or  

AE  

2

=AC  

2

+EC  

2

−2.AC.EC.cosC

Or

=4  

2

+(  

3

5

​  

)  

2

−2.8.  

3

5

​  

.cosC

=16+  

9

25

​  

−  

3

2×4×5

​  

.  

5

4

​  

 

Or

=  

9

169

​  

−  

3

32

​  

 

=  

9

169−96

​  

 

=  

9

73

​  

.

Hence

AE  

2

=  

9

73

​  

.

cosθ=  

2.AE.4

AE  

2

+4  

2

−  

3

5

​  

 

2

 

​  

 

=  

73

​  

 

8

​  

.

Hence

secθ=  

8

73

​  

 

​  

 

Now  

tanθ=  

sec  

2

θ−1

​  

 

=  

64

73

​  

−1

​  

 

=  

8

3

​  

.

solution

Expand-image

Correct option is

B

AE  

2

=  

9

73

​  

 

C

tanθ=  

8

3

​  

 

Hence

BD=DE=EC=  

3

5

​  

 and △ABC is a right angled triangle.

Now  

cosC=  

2.AC.EC

AC  

2

+EC  

2

−AE  

2

 

​  

 

Or  

AE  

2

=AC  

2

+EC  

2

−2.AC.EC.cosC

Or

=4  

2

+(  

3

5

​  

)  

2

−2.8.  

3

5

​  

.cosC

=16+  

9

25

​  

−  

3

2×4×5

​  

.  

5

4

​  

 

Or

=  

9

169

​  

−  

3

32

​  

 

=  

9

169−96

​  

 

=  

9

73

​  

.

Hence

AE  

2

=  

9

73

​  

.

cosθ=  

2.AE.4

AE  

2

+4  

2

−  

3

5

​  

 

2

 

​  

 

=  

73

​  

 

8

​  

.

Hence

secθ=  

8

73

​  

 

​  

 

Now  

tanθ=  

sec  

2

θ−1

​  

 

=  

64

73

​  

−1

​  

 

=  

8

3

​  

 

solution

Expand-image

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Answer:

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Step-by-step explanation:

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tankabanditka [31]

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5 0
3 years ago
I need help with this, neither of my parents can help me and i want to understand.
olga2289 [7]

Answer:

See explanation

Step-by-step explanation:

1. To rewrite the expression

(4^{\frac{2}{5}})^{\frac{1}{4}},

use exponents property

(a^m)^n=a^{m\cdot n}

So,

(4^{\frac{2}{5}})^{\frac{1}{4}}=4^{\frac{2}{5}\cdot \frac{1}{4}}=4^{\frac{2}{20}}=4^{\frac{1}{10}}

2. Why 10^{\frac{1}{3}}=\sqrt[3]{10}?

Raise both sides to 10 power:

(10^{\frac{1}{3}})^3=10^{\frac{1}{3}\cdot 3}=10^1=10\\ \\(\sqrt[3]{10})^3=10

So,

(10^{\frac{1}{3}})^3=(\sqrt[3]{10} )^3

3. Simplify \dfrac{3^4}{9}

Use  the Quotient of Powers Property:

\dfrac{a^m}{a^n}=a^{m-n}

Then

\dfrac{3^4}{9}=\dfrac{3^4}{3^2}=3^{4-2}=3^2

4. Solve 4\sqrt{2}+5\sqrt{4}

First, note that \sqrt{4}=2, then

4\sqrt{2}+5\sqrt{4}=4\sqrt{2}+5\cdot 2=4\sqrt{2}+10

Number 4\sqrt{2} is irrational number, number 10 is rational number. The sum of irrational and rational numbers is irrational number.

5. The same as option 4.

3 0
3 years ago
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