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sesenic [268]
3 years ago
10

To which subset of the real numbers does √2 belong

Mathematics
1 answer:
pishuonlain [190]3 years ago
4 0
It is an irrational number.

As a decimal, it equals 1.414235... This is a nonrepeating and nonterminating decimal, which makes it an irrational number, It also cannot be represented as a ratio of two integers.
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How do you do number 2? Help please and thank you.
Dmitrij [34]

Answer:

{3,-1}

Step-by-step explanation:

m^2 -2m -3=0

What 2 numbers multiply to -3 and add to negative 2

-3* 1 = -3

-3 +1 =-2

(m-3) (m+1) =0

Using the zero product property

m-3 = 0  m+1 =0

m=3        m=-1

{3,-1}

6 0
3 years ago
Find the slope of the line
Anvisha [2.4K]
The slope of the line is 5
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2 years ago
Can you round 14.392
seropon [69]

Answer:

the rounded answer is 14

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
the total number of living humans on arth was converted to scientific notation using an online caculation and was reported to be
gogolik [260]
7.158 * 10^9 rounds to 7 * 10^9
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6 0
3 years ago
Determine whether the statements are True or False. Justify your answer with an explanation.
frez [133]

Problem 1

<h3>Answer: False</h3>

---------------------------------

Explanation:

The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.

So,

f(x) = x+1

f( g(x) ) = g(x) + 1 .... replace every x with g(x)

f( g(x) ) = 6x+1 ... plug in g(x) = 6x

(f o g)(x) = 6x+1

Now let's flip things around

g(x) = 6x

g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)

g( f(x) ) = 6(x+1) .... plug in f(x) = x+1

g( f(x) ) = 6x+6

(g o f)(x) = 6x+6

This shows that (f o g)(x) = (g o f)(x)  is a false equation for the given f(x) and g(x) functions.

===============================================

Problem 2

<h3>Answer: True</h3>

---------------------------------

Explanation:

Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.

For example, let

f(x) = 1/(x+2)

g(x) = -2

The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.

So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).

7 0
3 years ago
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