We would have the following sample space:
(1, 1), (1, 2), (1, 3), (1, 4)
(2, 1), (2, 2), (2, 3), (2, 4)
(3, 1), (3, 2), (3, 3), (3, 4)
(4, 1), (4, 2), (4, 3), (4, 4)
Those give us these sums:
2, 3, 4, 5
3, 4, 5, 6
4, 5, 6, 7
5, 6, 7, 8
P(sum of 2) = 1/16 =0.0625
P(sum of 3) = 2/16 = 0.125
P(sum of 4) = 3/16 = 0.1875
P(sum of 5) = 4/16 = 0.25
P(sum of 6) = 3/16 = 0.1875
P(sum of 7) = 2/16 = 0.125
P(sum of 8) = 1/16 = 0.0625
Answer:
144 rupees
Step-by-step explanation:
2 kg= 24 rupees
2/2 kg= 24/2 rupees
1 kg= 12 rupees
1×12 kg= 12×12 rupees
12 kg= 144 rupees
B. the diagonals are congruent - the graph represents two equal, parallel lines, making the two segments congruent
Answer:
Coordinates of point P is 
.
Step-by-step explanation:
Given that mid point of line segment 
is at <em>M(-9, 8.5).</em>
Q is at <em>(-4, 14)</em>.
Let coordinate of P be 
.
Using the ratio, we can say the following:
<em>The coordinates of mid point</em> 
of a line with endpoints 
and 
is given as:
Using the formula for above given dimensions:
So, the <em>coordinates of point P are</em> .
Use trigonometry.
sinQ = 14/50 = 0.28
-> angle Q = sin^-1(0.28) = approx 16 degrees
-> cosQ = A/H -> cos16 = PQ/50
=> PQ = 50*cos16 = approx 48.06
So yea.
