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Black_prince [1.1K]
4 years ago
6

A line includes the points (1, 9) and (0, 5). What is it’s equation in the slope-intercept form?

Mathematics
1 answer:
scoundrel [369]4 years ago
5 0

Equation is y = 4x + 5

Step-by-step explanation:

  • Step 1: Find the slope of the line by m = (y2 - y1)/(x2 - x1). Here y2 = 5, y1 = 9, x1 = 1 and x2 = 0

⇒ m = (5 - 9)/(0 - 1) = 4

  • Step 2: Find y-intercept, b. Since the line passes through (0, 5) b = 5
  • Step 3: Write the equation in slope-intercept form

⇒ y = 4x + 5

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Given the relation in the table, what is the product of h(3) and h(5)?​
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Secant jkl and jmn are drawn to circle o from an external point ,j. if jk=8,lk=4 and jm=6 what is the length of jn answer
Archy [21]
See the picture attached to better understand the problem

we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
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kati45 [8]

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B(10,000 , 0.00005)

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3 0
3 years ago
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