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ella [17]
3 years ago
12

Children of mothers who smoked during pregnancy scored nine points lower on intelligence tests at ages three and four than child

ren of nonsmokers.
1. Suggest some lurking variables that may help explain the association between smoking during pregnancy and children's later test scores. The association by itself is not good evidence that mothers' smoking causes lower scores. (Select all that apply.)a. The diet of the child.
b. The psychological condition of the child.
c. The IQ of the mother.
d. The socioeconomic status of the mother.
Mathematics
1 answer:
eduard3 years ago
8 0

Answer:

All of the options apply.

Step-by-step explanation:

In the example given in the question, it is stated that mothers' smoking during pregnancy can affect childs' IQ and can cause lower scores on test.

All of the given options can be given as evidence for the link between smoking and lower IQ. The diet especially throughout childhood has significant effect on the development of the brain and the prefrontal cortex.

The psychological condition that the child is in, the environment in the house that he/she grows up in affects the IQ and the EQ.

The IQ can be affected by outside factors but it also has a relation with the genes that the child takes from his/her parents.

The socioeconomic status of the mother can affect the environment that the child grows up in, the people he/she interacts with and the opportunities that he/she gets to stimulate the brain in different ways to encourage growth.

I hope this answer helps.

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<h3>Answer:   54</h3>

==============================================

Work Shown:

T = tens digit

U = units digit (aka ones digit)

A number like 27 is really 20+7 = 2*10 + 7*1 = 10*2 + 1*7. We have 2 in the tens digit and 7 in the units digit. So 27 can be written in the form 10T + U where T = 2 and U = 7. Reversing the digits gives 72, so T = 7 and U = 2 now. Clearly the difference between the digits 7 and 2 is not 1, so 27 or 72 is not the answer (as it's just an example).

-----------------------

Let T be larger than U. This doesn't work if T = U.

Because T is larger, saying "The difference between the digits is 1" means T - U = 1. We can isolate T to get T = U+1. We'll use this later.

-----------------------

If T > U, then the original number 10T+U reverses to the new number 10U+T and it becomes smaller. We are told that it becomes 5/6 of what it used to be.

So,

new number = (5/6)*(old number)

10U + T = (5/6)(10T + U)

6(10U + T) = 5(10T + U)

60U + 6T = 50T + 5U

60U + 6(U+1) = 50(U+1) + 5U ... plug in T = U+1

60U + 6U + 6 = 50U + 50 + 5U

66U + 6 = 55U + 50

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T = 4+1

T = 5 is the tens digit of the original number

The original number is therefore 10T + U = 10*5+4 = 54.

We see the difference in their digits is T-U = 5-4 = 1

The reverse of 54 is 45. The number 45 is 5/6 of 54

45 = (5/6)*54

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3 years ago
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