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Mekhanik [1.2K]
3 years ago
8

Can someone plzzz help me

Mathematics
1 answer:
faust18 [17]3 years ago
7 0
It’s f(0)=3 because f(0) just means y intercept which is 3
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How many times does 12 go into 75
katovenus [111]

12 goes into 75 6 times with a remainder of 3. So the answer will be 6 remainder 3

4 0
3 years ago
Pls help me I don’t get it
Minchanka [31]

Answer: C

Step-by-step explanation: Hope this help :D

4 0
2 years ago
Read 2 more answers
F(n+1)=f(n)-5. If f(1)=100, what is f(6)
PilotLPTM [1.2K]

Answer:

<em>75</em>

Step-by-step explanation:

Given:

f(1) = 100

f(n+1) = f(n) - 5

Solve for:

f(6)

Solution:

f(1) = 100

f(2) = f(1) - 5 = 100 - 5 = 100 - 1 x 5 = f(1) - 1 x 5

f(3) = f(2) - 5 = 100 - 5 - 5 = 100 - 2 x 5 = f(1)  - 2 x 5

...

f(n) = f(n - 1) - 5 = 100 - (n-1) x 5 = f(1) - (n-1) x 5

=> f(6) = f(1) - (6-1) x 5 = 100 - 5 x 5 = 100 - 25 = 75

Hope this helps!

8 0
3 years ago
Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li
krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

Therefore the half-life is between 600 and 700 years

5 0
3 years ago
A cashier has 26 bills consisting of three times as many ones as fives, one less ten than fives, and the rest twenties. If the v
monitta
Let number of  fives = x then number of ones = 3x  and number of tens = x - 1

so we can create the equation 

x + 3x +  x-1 + y = 26  where y = number of twenties
so
5x + y = 27

also we have the equation 

5x + 3x + 10(x - 1) + 20y = 120

18x + 20y = 130..................................(1)
5x    + y    = 27     multiply  by -20:-
-100x - 20y = -540..............................(2)
Adding equation (1) and (2)
-82x = -410
x  = 5,  that is  5 fives

Now plug x = 5 into equation 1:-
18(5) + 20y = 130
20y =  40
y =  2 ,   that is 2 twenties

So the answer is   there are (3x) = 15 ones , 5  fives, 4 tens and 2 twenties
7 0
3 years ago
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