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GenaCL600 [577]
3 years ago
9

Please help me......

Mathematics
2 answers:
likoan [24]3 years ago
7 0

Answer:

\frac{3}{8}

Step-by-step explanation:

A=6*\frac{1}{4} ^2\\\\A=6*\frac{1}{16} \\\\A=\frac{6}{16} \\\\A=\frac{3}{8}

Kitty [74]3 years ago
6 0

Answer:

A = \frac{3}{8}ft^2

Step-by-step explanation:

Using the given formula, A=6s^2, and the given value for the side length of the cube, \frac{1}{4} foot, substitute the given value into the equation and solve.

A=6(\frac{1}{4})^2

Remember, setting any value to the second power is the same as multiplying the base (the value that is being squared) by itself. Apply this information to the given problem,

A = 6(\frac{1}{4}*\frac{1}{4})\\\\A = 6(\frac{1}{16})\\\\A = \frac{6}{16}\\\\A = \frac{3}{8}

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Find the distance between two points ( -1,1) and (2,-4)
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Answer:

The distance between two points ( -1,1) and (2,-4) is:

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Step-by-step explanation:

Given the points

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  • (2, -4)

Finding the distance between (-1, 1) and (2, -4) using the formula

d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

substitute (x₁, y₁) =  (-1, 1)   and  (x₂, y₂) = (2, -4)

   =\sqrt{\left(2-\left(-1\right)\right)^2+\left(-4-1\right)^2}

   =\sqrt{\left(2+1\right)^2+\left(-4-1\right)^2}

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   =\sqrt{9+25}

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d = 5.8 units

Therefore, the distance between two points ( -1,1) and (2,-4) is:

d=\sqrt{34}  or d = 5.8 units.

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