Please see the explanation of this question to see procedure for the dilation of the triangle ABC and the image attached below to know the result.
<h3>How to generated a resulting triangle by transformation rules</h3>
In this question we must apply a kind of <em>rigid</em> transformation known as dilation. A dilation of a point around a point of reference is defined by the following operation:
P'(x, y) = O(x, y) + k · [P(x, y) - O(x, y)] (1)
Where:
- O(x, y) - Point of reference
- k - Dilation factor
- P(x, y) - Original point
- P'(x, y) - Resulting point
Let assume that the point P is the origin of a <em>rectangular</em> system of coordinates. Then, the coordinates of the three vertices of the triangle ABC respect to the origin are: A(x, y) = (- 1, 2), B(x, y) = (- 1, - 1), C(x, y) = (2, 0).
Then, the vertices of the resulting triangle A'B'C' are, respectively:
A'(x, y) = (0, 0) + 3 · [(- 1, 2) - (0, 0)]
A'(x, y) = (- 3, 6)
B'(x, y) = (0, 0) + 3 · [(- 1, - 1) - (0, 0)]
B'(x, y) = (- 3, - 3)
C'(x, y) = (0, 0) + 3 · [(2, 0) - (0, 0)]
C'(x, y) = (6, 0)
Finally, we draw the resulting triangle with the help of a graphing tool.
To learn more on dilations: brainly.com/question/13176891
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Answer:
B.) y = -3/2<em>x</em> + 5
Step-by-step explanation:
Write in slope-intercept form, y=mx+b
5/54 or approximately 0.092592593
There are 6^3 = 216 possible outcomes of rolling these 3 dice. Let's count the number of possible rolls that meet the criteria b < y < r, manually.
r = 1 or 2 is obviously impossible. So let's look at r = 3 through 6.
r = 3, y = 2, b = 1 is the only possibility for r=3. So n = 1
r = 4, y = 3, b = {1,2}, so n = 1 + 2 = 3
r = 4, y = 2, b = 1, so n = 3 + 1 = 4
r = 5, y = 4, b = {1,2,3}, so n = 4 + 3 = 7
r = 5, y = 3, b = {1,2}, so n = 7 + 2 = 9
r = 5, y = 2, b = 1, so n = 9 + 1 = 10
And I see a pattern, for the most restrictive r, there is 1 possibility. For the next most restrictive, there's 2+1 = 3 possibilities. Then the next one is 3+2+1
= 6 possibilities. So for r = 6, there should be 4+3+2+1 = 10 possibilities.
Let's see
r = 6, y = 5, b = {4,3,2,1}, so n = 10 + 4 = 14
r = 6, y = 4, b = {3,2,1}, so n = 14 + 3 = 17
r = 6, y = 3, b = {2,1}, so n = 17 + 2 = 19
r = 6, y = 2, b = 1, so n = 19 + 1 = 20
And the pattern holds. So there are 20 possible rolls that meet the desired criteria out of 216 possible rolls. So 20/216 = 5/54.