Ask question

Ask question

All categories

Mekhanik [1.2K]

2 years ago

12

To order tickets online to a hockey game, there is a processing fee plus the cost per ticket. The cost for 5 tickets is $174.45.

The codt for 8 tickets is $271.95. Write and solve a linear equation to find the total cost to order 13 tickets.

1 answer:

xeze [42]2 years ago

3 0

Wouldn’t the total for 13 tickets be $446.40 ? We already know the cost for 5 and 8 just add it up .... js

You might be interested in

4. Kevin has $24 to buy a gift for his cousin.

Roman55 [17]

Answer: Yes, he would have enough money. In total he would spend $23.10

Step-by-step explanation

Add 5% to the $24

4 0

2 years ago

If a=2b^3 and b= -1/2c ^-2,express a in terms of c.

ElenaW [278]

Answer:

Part 1) $a=-\frac{1}{4c^6}$

Part 2) $a=-\frac{1}{4c^{-6}}$

Step-by-step explanation:

Part 1) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2}c^{-2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{1}{2}c^{-2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}$

therefore

$a=-\frac{1}{4c^6}$

Part 2) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{c^{2}}{2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})$

simplify

$a=-\frac{c^{6}}{4}$

therefore

$a=-\frac{1}{4c^{-6}}$

6 0

2 years ago

60 pointssss!!!!! Need Help ASAP

Lerok [7]

Why Brainly capping

6 0

2 years ago

3. A positive number is 56 less than its square. Find the number.

raketka [301]

Answer:8

Step-by-step explanation:

X+56=x^2

X^2-x-56=0

X^2-8x+7x-56=0

X(x-8)+7(x-8)=0

(X+7)(x-8)=0

X+7=0 or x-8=0

X=-7 or x=8

4 0

2 years ago

1 2 3 4 5 6 7 8 9 10 TIME REMAINING 57:13 A particular beach is eroding at a rate of 4 centimeters per year. A realtor converts

jok3333 [9.3K]

$\dfrac{4 \textrm{ cm}}{\textrm{year}} \times \dfrac{\textrm{year}}{365 \textrm{ days}} \times \dfrac{10\textrm{ mm}}{\textrm{cm}} = \dfrac{8}{73} \approx 0.1 \textrm{ mm per day}$

Answer. About 0.1 mm/day

3 0

2 years ago