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Wittaler [7]
3 years ago
14

can julia cut a triangular patch for a quilt that has side lengths 1 1/2 inches, 2 inches, and 4 inches? i need the explanation

and the correct answer.
Mathematics
1 answer:
mixer [17]3 years ago
3 0
Yes. A triangle with three sides given can be cut out.
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These box plots show the basketball scores for two teams
Alex

Answer: B

Step-by-step explanation:

7 0
3 years ago
Andrew is painting a wall on the side of his house. He has a 20 foot ladder wich makes a 79 degree angle with the ground. Standi
torisob [31]

Andrew can reach a maximum of 24.6ft high up the wall.

The right-angled triangle formed can be solved using the sine ratio. that is

sin(72^\circ})=\dfrac{h}{20}

where h is the distance from the foot of the wall to the tip of the ladder where it rests on the wall. Substituting, and solving for h, we get

0.9816=\dfrac{h}{20}\\\\h=20\times0.9816\\\\h=19.632ft

Since Andrew can reach an extra 5ft above the point where the ladder rests against the wall, the maximum height Andrew can paint is

(19.632+5)ft=24.632ft\\\\\approx24.6ft

Another solved word problem on trigonometry can be found here: brainly.com/question/12146092

3 0
3 years ago
Solve for .....x <br><br><br> 2x+8=4
Naya [18.7K]

Answer:

2x=-4

x=-2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Can you guy's please help me out I was absent and now I don't have a clue!
Elena-2011 [213]
For these problems you have to use PEMDAS so for problem 15 you would do the parentheses first, (21-3) you get 18 and then exponents, 3^2, you get 9, no multiplication but there is division so take your answers, 18 and 9 and divide them, you get 2, so the answer to 15 is 2.
6 0
4 years ago
Two sections of a class took the same quiz. Section A had 15 students who had a mean score of 80, and Section B had 20 students
Nezavi [6.7K]

Answer: A. 85.7

Step-by-step explanation:

Given : Two sections of a class took the same quiz.

Section A had 15 students who had a mean score of 80, and Section B had 20 students who had a mean score of 90.

We know that  , \text{Mean}=\dfrac{\text{Sum of observations}}{\text{No. of observations}}

Then , for section A :

\text{Mean score }=\dfrac{\text{Sum of scores in sec A}}{\text{No. of students}}

\Rightarrow\ 80=\dfrac{\text{Sum of scores in sec A}}{15}\\\\\Rightarrow\ \text{Sum of scores in sec A}=80\times15=1200

Similarly in Section B, \text{Sum of scores in sec B}=90\times20=1800

Total scores = Sum of scores in sec A+Sum of scores in sec B

=1200+1800=3000

Total students = Students in sec A +Students in sec B

=15+20=35

Now , the mean score for all of the students on the quiz =\dfrac{\text{Total score}}{\text{Total students}}

=\dfrac{3000}{35}=85.7142857143\approx85.7

Hence, the approximate mean score for all of the students on the quiz = 85.7

Thus , the correct answer is option A. 85.7.

7 0
3 years ago
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