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Sav [38]
3 years ago
14

What expressions are equivalent to 4(4a+5) which 3 is correct?

Mathematics
1 answer:
Effectus [21]3 years ago
7 0
The answer is a,c, and d
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Use the parabola tool to graph the quadratic function f (x) = 2x2 - 4x + 6.
lubasha [3.4K]

Answer:

Vertex plot is (1,4)

and

second plot point (0,6)

Step-by-step explanation:

You can use the the desmos graph calculator by entering quadratic function f(x) = 2x^2 − 4x + 6

3 0
3 years ago
Which of the following best describes a line
finlep [7]

I would answer, but you didn't give any options.

6 0
3 years ago
Read 2 more answers
Can you help me please?
MrRa [10]

Answer:

B.

Step-by-step explanation:

The least amount of water in a pool is zero gallons.

It takes 16 minutes to reach zero gallons (the pool is empty).

The domain is from 0 to 16.

Answer: B.

8 0
4 years ago
Can someone please help and show work
Bad White [126]
Answer:$8.60
I put the work into the picture. Hope this helps!

7 0
3 years ago
Find an equation for the line with the given properties. Perpendicular to the line x - 6y = 8; containing the point (4,4) O 1) y
Pepsi [2]

Answer:

Option 3 - y=-6x+28

Step-by-step explanation:

Given : Perpendicular to the line x - 6y = 8; containing the point (4,4).

To Find : An equation for the line with the given properties ?

Solution :

We know that,

When two lines are perpendicular then slope of one equation is negative reciprocal of another equation.

Slope of the equation x - 6y = 8

Converting into slope form y=mx+c,

Where m is the slope.

y=\frac{x-8}{6}

y=\frac{x}{6}-\frac{8}{6}

The slope of the equation is m=\frac{1}{6}

The slope of the perpendicular equation is m_1=-\frac{1}{m}

The required slope is m_1=-\frac{1}{\frac{1}{6}}

m_1=-6

The required equation is y=-6x+c

Substitute point (x,y)=(4,4)

4=-6(4)+c

4=-24+c

c=28

Substitute back in equation,

y=-6x+28

Therefore, The required equation for the line is y=-6x+28

So, Option 3 is correct.

8 0
3 years ago
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