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Marrrta [24]
2 years ago
12

Sam mows a ¼ of a lawn in ½ of an hour. At this rate, how long will it take him to finish one lawn?

Mathematics
2 answers:
photoshop1234 [79]2 years ago
5 0
2 hours if he mows 1/4 im 1/2 then 2/4 would be 1 hour then 3/4 would be 1 1/2 hour then 4/4 would be 2 hours so ur answer is 2 hours
Scorpion4ik [409]2 years ago
4 0

Answer:

Two hours

Step-by-step explanation:

1/4 = 1/2

2/4 = 1

3/4 = 1 1/2

4/4 = 2

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22 represents how much she gets paid by the hour

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To purchase $12,900 worth of machinery for her business, Melissa made a down payment of $2100 and took out a business loan for t
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Answer:

a) $13588.08

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Step-by-step explanation:

Melissa had to purchase $12,900 worth of machinery for her business.

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Given that after years of paying monthly payments of $478.67, she finally paid off the loan.

Assume that she took 2 years to repay the loan.

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b) Therefore, the amount of interest that Melissa pay on the loan is $(13588.08 - 12900) =$688.08. (Answer)

4 0
3 years ago
christa buys an alarm clock for 45% the store increases the purchase price of the clock by 150%? what is the new sales price of
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A scale drawing of an American flag is 10 inches and 6 inches tall the actual flag is 3 feet tall. What is the area of the actua
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3 years ago
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

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