Daughters get one X gene from each parent.
If the father is a normal male, he carries only a normal X-gene.
Therefore the daughter will always get a normal gene from the father, and a 50% probability getting an affected gene from the mother, therefore 50% chance of becoming a carrier. The other 50% she will inherit a normal X-gene from each parent, thus a healthy female.
In conclusion, no daughter will have haemophilia from a carrier mother and a normal male.
(however, sons will have a 50% chance of inheriting affected X-gene and hence will have haemophilia).
the correct answer is c I believe
Answer:
A female Drosophila of unknown genotype was crossed with a white-eyed male fly, of genotype (w = white eye allele is recessive, w+= red-eye allele is dominant.) Half of the male and half of the female offspring were red-eyed, and half of the male and half of the female offspring were white-eyed.If the trait is dominant, one of the parents must have the trait. Dominant traits will not skip a generation. If the trait is recessive, neither parent is required to have the trait since they can be heterozygous.The female fly had to be heterozygous, Xw+ Xw.
Explanation:
I believe the answer you're looking for is Evolution.
