A and C are correct. It is worth noting that all cells have DNA.
Answer:
The results can be explained if the mutation for bag wings is sex-linked, dominant, and lethal in males.
Explanation:
When a trait is differently expressed in males and females, we must suspect that it's sex-linked.
If we consider the mutation for bag wings as sex-linked and dominant (B), and the wild-type allele (B+) is recessive, then the<u> expected offspring</u> resulting from the cross between a bag-winged female XᴮXᴮ⁺ (heterozygous) and a WT male Xᴮ⁺Y would be:
- 1/4 XᴮXᴮ⁺ bag-winged female
- 1/4 Xᴮ⁺Xᴮ⁺ wild-type female
- 1/4 Xᴮ⁺Y wild-type male
- <u><em>1/4 XᴮY bag winged male</em></u>
But the bag-winged male doesn't appear in the progeny, and the observed proportions of the other phenotypes are 1/3 each. This suggests that the mutation is lethal in males, and maybe in homozygosis in females as well.
Answer:
I would say prophase of mitosis is The chromosomes have stretched out