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Blizzard [7]
2 years ago
15

What is the slope of a line perpendicular to the line whose equation is 2x-y=5 ?

Mathematics
1 answer:
mariarad [96]2 years ago
3 0

Answer:

-1/2

Step-by-step explanation:

the slope of the line 2x-y=5 is 2

a perpendicular line has the negative reciprocal of the slope of the other line

hopefully this helps :)

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Please help me with mathematics
klasskru [66]

Answer:8

Step-by-step explanation:if im wrong sorry

6 0
3 years ago
Need an answer asap!!!! <br> a = 12, b = 5, and c = 4.<br> 3c + bc - 2a
Serhud [2]

Answer:

8

Step-by-step explanation:

3(4)+(5)(4)-2(12)

then solve

12+20-24=8

6 0
3 years ago
A bookstore contains 75972 books,divided in to three sections. The science represents 1/3 of the total books. The remaining book
S_A_V [24]

Answer:

12,662 books

Step-by-step explanation:

Total number of books = 75,972

No. of science books = ⅓ of 75,972 = ⅓*75,972 = 25,324 books.

No. of business books = 75% of the remaining books = 75% of (75,972 - 25,324)

= \frac{75}{100}*50,648 = 37,986

No. of business books = 37,986

No. of maths books in the math section = 75,972 - (25,324 + 37,986)

= 75,972 - 63,310

= 12,662 books

7 0
3 years ago
Which are the solutions of x^2 = –11x + 4?
strojnjashka [21]

This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

x^2 + 11x - 4 = 0

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}

where x_{1,2} is a compact way to indicate both solutions x_1 and x_2, while a,b,c are the coefficients of the quadratic equation, i.e. we consider the polynomial ax^2+bx+c.

So, in your case, we have a=1,\ \ b=11,\ \ c=-4

Plug those values into the formula to get

x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}

So, the two solutions are

x_1 = \frac{-11+\sqrt{137}}{2}

x_2 = \frac{-11-\sqrt{137}}{2}

3 0
3 years ago
Brandon has 32 stamps. he wants to display the stamps in rows,with the same n
AleksandrR [38]
Okay, let's work this out...
What we know:
-32 stamps in all
- rows (horizontal)
- same # in each
What we "want to know" :
- # of combinations (different)
Problem Solving :
This is actually very easy its just the words than get ya!
1st : we need to figure out the factors of 32...
In other words, we need to figure out _x_=32 and how many different combinations and ways there are!
Note:(* means multiplication)
#1: What are the factors of 32?
32: 1*32 , 2*16 , 4*8
32: 32*1 , 16*2 , 8*4
The factors (not including 1 are 2,4,8,16)
Now, as you can see, there are 4 ways to get 32 as shown first.
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That ¦ is 1 way with 16 in 2 rows. Basic multiplication, 16*2=32 or 16+16=32.
But, this is also a way,
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Now there should be 2 in each row and 16 rows. Again 2*16=32 or 2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2=32
That's two ways so far.
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Another way which is 4 rows with 8 in each.
4*8=32 or 8+8+8+8=32
But, this is also a way,
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Now that is 8 rows with 4 in each. 8*4=32 or 4+4+4+4+4+4+4+4=32
That was our fourth way.
Again NOT including 1. If you include 1 then there will be 6 ways but aside from that there are 4 ways.
I hope that helped I worked hard typing this all for you. Any questions just ask!
3 0
2 years ago
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