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Blizzard [7]
2 years ago
15

What is the slope of a line perpendicular to the line whose equation is 2x-y=5 ?

Mathematics
1 answer:
mariarad [96]2 years ago
3 0

Answer:

-1/2

Step-by-step explanation:

the slope of the line 2x-y=5 is 2

a perpendicular line has the negative reciprocal of the slope of the other line

hopefully this helps :)

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∠C and ​ ∠D ​ are vertical angles with m∠C=−3x+58 and m∠D=x−2 .<br><br><br><br> What is m∠D ?
11111nata11111 [884]
Vertical angles are equal

-3x + 58 = x - 2
-3x - x = -2 - 58
-4x = - 60
x = -60/-4
x = 15

m < D = x - 2....15 - 2 = 13 <====
m < C = -3x + 58....-3(15) + 58 = 13 
4 0
3 years ago
Read 2 more answers
Round 35295 to the nearest thousand
Alex_Xolod [135]

35000, rounding down from five.

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3 years ago
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Paula's dog Toby, weighs 95 pounds to find Toby's weight in kilograms, what conversion factor should you use?
Anettt [7]
One pound is about 0.5, so pretty much divide it by half
7 0
3 years ago
If EF bisects CD.CG = 5x - 1, GD = 7x-13, EF = 6x - 4, and GF = 13. find EG.
Iteru [2.4K]

Answer:

EG = 19

Step-by-step explanation:

* Lets explain how to solve the problem

- If a line bisects another line that means the point of intersection

 divides the second line into two equal parts

∵ EF bisects CD at G

∴ CG = GD

∵ CG = 5x - 1

∵ GD = 7x - 13

∴ 7x - 13 = 5x - 1

* Lets solve the equation

∵ 7x - 13 = 5x - 1

- Subtract 5x from both sides and add 13 to both sides

∴ 7x - 5x = 13 - 1

∴ 2x = 12

- Divide both sides by 2

∴ x = 6

- Point G divides EF into two parts EG and GF

∴ EF = EG + GF

∵ EF = 6x - 4

- Substitute the value of x to find EF

∵ x = 6

∴ EF = 6(6) - 4 = 36 - 4 = 32

∴ EF = 32

∵ GF = 13

- Substitute the values of EF and GF in the equation of EF

∴ 32 = EG + 13

- Subtract 13 from both sides

∴ 19 = EG

* EG = 19

3 0
3 years ago
a bricklayer needs to order 6300kg of building sand.one grain of this sand weighs 7x10^-5. how many grains of sand are there in
gavmur [86]

Answer:

44.1 x 10^-2

Step-by-step explanation:

Since one grain

= 7 x 10^-5

6300kg = 7 x 10^-5 x 6300

Put 6300 in standard form

7 x 10^-5 x 6.3 x 10^3

Multiply the whole numbers and add the exponents

7 x 6.3 x 10^-5 + 3

44.1 x 10^-2

There are 44.1 x 10^-2 grains of sand in 6300kg

5 0
2 years ago
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