Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
The answer is C because if you put
Find the reflected two points which are:
They're just flipped equations
To change a decimal to a fraction you need to first place the decimal over 1. Next, for each number behind the decimal, you will multiply by a multiple of 10. Since there are 2 numbers behind the decimal, it's 100. Therefore,
92.96 x 100 = 9296
1 x 100= 100
Your new fraction is 9296/100. Now we simplify it. I'm going by 2's so it may take a bit.
Simplifying it twice by 2's your answer would be:
2324/25
Answer:
José has 49 used stamps
Step-by-step explanation:
7 used stamps for every 4 new stamps
To solve this type of problem, we can use a ratio
7 : 4 ratio
He has 28 new stamps
7 : 4 = x : 28
Ratios can be written as fractions
Cross multiply
4x = 7(28) = 196
Divide by 4 on both sides
x = 49
Hope this helps :)
Answer:
The difference in the areas of the cross-sections is 20 m².
Step-by-step explanation:
^^^
