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Paha777 [63]
3 years ago
12

During the election of 1824, Jackson won the popular vote, but no canididate won a mojority of the electoral votes. How was this

issue resolved?
Mathematics
1 answer:
Reil [10]3 years ago
4 0
The cabinet got do deside I think sorry if I’m wrong
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Can you show me how to solve this?
ollegr [7]

Answer:

see below

Step-by-step explanation:

9x-y =8    re-arrange

y = 9x -8      slope , m = 9     parallel slope is the same = 9

point slope form thru point 4,4

y-4 = 9 ( x-4)

y-4 = 9x - 36

y = 9x -32        

y - 9x = -32

9x-y = 32

4 0
1 year ago
Please help me out with this problem!
ANEK [815]

Answer:

-7 × 6

Step-by-step explanation:

-7×6 = -42

-7+6= -1

hope u can understand

4 0
3 years ago
Melissa has 56 pens and 37 more pencils than pens. How many pencils did Melissa have?
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Melissa had nineteen pencils
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4 years ago
Read 2 more answers
How do you graph the trigonometric function y= -sin(2x)+1?
Naddik [55]

Answer:

Graph the trigonometric function using the amplitude, period, phase shift, and vertical shift.

Amplitude:  1

Period:  π

Phase Shift: 0  ( 0  to the right)

Vertical Shift: 1

4 0
4 years ago
the name Joe is very common at a school in one out of every ten students go by the name. If there are 15 students in one class,
kumpel [21]

Using the binomial distribution, it is found that there is a 0.7941 = 79.41% probability that at least one of them is named Joe.

For each student, there are only two possible outcomes, either they are named Joe, or they are not. The probability of a student being named Joe is independent of any other student, hence, the <em>binomial distribution</em> is used to solve this question.

<h3>Binomial probability distribution </h3>

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • One in ten students are named Joe, hence p = \frac{1}{10} = 0.1.
  • There are 15 students in the class, hence n = 15.

The probability that at least one of them is named Joe is:

P(X \geq 1) = 1 - P(X = 0)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{15,0}.(0.1)^{0}.(0.9)^{15} = 0.2059

Then:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2059 = 0.7941

0.7941 = 79.41% probability that at least one of them is named Joe.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

8 0
3 years ago
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