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nexus9112 [7]
3 years ago
15

(-15)+(-3)=0+15-3= 12

Mathematics
2 answers:
Kobotan [32]3 years ago
5 0

(-15)+(-3)

(-15)-3

<u>-18</u>

Ostrovityanka [42]3 years ago
4 0

Answer:

Step-by-step explanation:

Because negative plus a negative, should be more of the negative.

So -15 + -3 = -18

Don't forget to note (-) in front of the number.

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(x³ + ³) / (x - y)<br> Do not include parentheses in your answer.
Lubov Fominskaja [6]

The simplified expression of \frac{x^3 + (-y)^3}{(x - y} is x^2+xy+y^2

<h3>Complete question</h3>

Simplify the expression: (x³ + (-y)³) / (x - y)

Do not include parentheses in your answer.

<h3>How to simplify the expression?</h3>

The expression is given as:

\frac{x^3 + (-y)^3}{(x - y}

Open the inner bracket

\frac{x^3 -y^3}{(x - y}

Apply the difference of two cubes to the numerator

\frac{(x-y)(x^2+xy+y^2)}{(x - y}


Cancel out the common factors

x^2+xy+y^2

Hence, the simplified expression of \frac{x^3 + (-y)^3}{(x - y} is x^2+xy+y^2

Read more about expressions at:

brainly.com/question/723406

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If the dimensions of a circle are tripled, the area of the resulting circle will also be three times larger.
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Answer:

Hello,

Step-by-step explanation:

A=(1,2)\\B=(0,-1)\\\overrightarrow{AB}=((0,-1)-(1,2)=(-1,-3)\ ||\overrightarrow{AB}||^2=1+9=10\\\overrightarrow{BC}=((3,-2)-(0,-1)=(3,-1)\ ||\overrightarrow{BC}||^2=9+1=10\\\\Triangle\ is\ isosceles.\\\\\overrightarrow{AB}.\overrightarrow{BC}=(-1,-3)*\left[\begin{array}{c}3\\-1\end{array}\right] =-3+3=0\\\\Triangle \ is\ right.\\\\

8 0
3 years ago
Read 2 more answers
The function y= -16t^2 +24t represents the height y (in feet) of a tennis ball bouncing straight up from the ground t seconds af
taurus [48]
We want to know the time, <em>t</em>, it takes the ball to reach a height (<em>y</em>) of 0.
0=-16t^2+24t
We can factor out the GCF first.  The largest number that will divide evenly into 16 and 24 is 8.  Also, both terms have a <em>t</em>, so we can factor that out as well:
0=8t(-2t+3) (-16/8 = -2 and 24/8 = 3)
Using the zero product property, we know that either 8t=0 or -2t+3=0.  Solving the first equation, we would divide both sides by 8:
8t/8=0/8
t=0
This is at 0 seconds, before the ball is in the air at all.
Solving the second equation, we start by subtracting 3 from both sides:
-2t+3-3=0-3
-2t=-3
Now we divide both sides by -2
-2t/-2=-3/-2
t=1.5
After 1.5 seconds, the ball will hit the ground again.
5 0
4 years ago
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