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aksik [14]
3 years ago
11

Find the x-coordinate of the vertex of the graph of the equation y=-3x^2+6x+2

Mathematics
1 answer:
Ivanshal [37]3 years ago
4 0
Consider, pls, this solution:
according to the equation y= -3x²+6x+2, where a=-3, b=6 and c=2, and the rule x₀= -b/(2a):
<u>x₀=</u>-6/(-6)<u>=1</u>.
For more info see the attached graph.

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The graph of a proportional relationship passes through (12, 16)<br> and (1, y)<br> . Find y
k0ka [10]

Answer: The value of y is \frac{4}{3}.

Explanation:

It is given that the graph of a proportional relationship passes through (12, 16)

and (1, y).

The graph of a proportional relationship means the x and y coordinates are in a proportion k. The equation of the graph is in the form of y=kx. Where k is the proportion factor.

It is given that the graph passing through (12,16).

y=kx

16=k(12)

k=\frac{16}{12}

k =\frac{4}{3}

So the equation of the line is,

y=\frac{4}{3} x

put x=1.

y=\frac{4}{3} (1)

y=\frac{4}{3}

Therefore, the value of y is \frac{4}{3}.

8 0
3 years ago
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If an area of a circle is 58 square feet find the circumference
mash [69]
26.99 square feet or just feet
5 0
3 years ago
Find the angles between -pi and pi that satisfy:<br><br> (−√3) sin(v)+cos(v)=√3
MAXImum [283]

Observe that

\sin\left(\dfrac\pi6-v\right)=\sin\dfrac\pi6\cos v-\cos\dfrac\pi6\sin v=\dfrac12\cos v-\dfrac{\sqrt3}2\sin v

In the original equation, divide both sides by \dfrac12:

-\sqrt3\sin v+\cos v=\sqrt3\implies\dfrac12\cos v-\dfrac{\sqrt3}2\sin v=\dfrac{\sqrt3}2

\implies\sin\left(\dfrac\pi6-v\right)=\dfrac{\sqrt3}2

Next,

\sin x=\dfrac{\sqrt3}2\implies x=\dfrac\pi3+2n\pi,x=\dfrac{2\pi}3+2n\pi

where n is any integer. Then

\sin\left(\dfrac\pi6-v\right)\implies v=-\dfrac\pi6-2n\pi,v=-\dfrac\pi2-2n\pi

Fix n=0 to ensure -\pi, so that

v=-\dfrac\pi6,v=-\dfrac\pi2

3 0
3 years ago
Can y’all help with this :)))))
cricket20 [7]
There’s a pattern to this and I’ll explain in the comments if you want to know or can’t figure it out :)


1.) 27/x^3

2.) a^8/b^12

3.) 7^36/81 OR 13,841,287,201/81

4.) 256m^20/n^4

5.) x^6y^6

6.) 64k^4/k^6

7.) 1,000a^9b^6/a^6b^9

8.) 81x^21/625

9.) 2304/x^16y^12

10.) x^7z^14/y^21

11.) 7,776k^5

12.) x^24y^24/4,096


Hope it’s all helped

7 0
3 years ago
What is the negative coterminal angle of 165 degrees ?
kipiarov [429]

Answer:

-195 degrees

Step-by-step explanation:

we can subtract 360 from 165 to find the negative coterminal angle.

165-360=-195

8 0
3 years ago
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