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3 years ago

What is the name of the type of data that a scatterplot is used to analyze?

Mathematics

1 answer:

earnstyle [38]3 years ago

5 0

Answer:

Bivariate Data :)

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14. Which of the following pairs of equation are equivalent

Bogdan [553]

Answer:

the second equatin

2x+(-6)=14 that give x=10 and the other 2x=14+6 gives x= 10 so this pair is equal

5 0

3 years ago

What is the coefficient of 12s + 4t

marshall27 [118]

Answer:

12 and 4

Step-by-step explanation:

it is the number being multiplied by the variable

Pls vote me brainliest

5 0

2 years ago

Find the sum of the geometric series 512+256+ . . .+4

mario62 [17]

$\bf 512~~,~~\stackrel{512\cdot \frac{1}{2}}{256}~~,~~...4$

so, as you can see above, the common ratio r = 1/2, now, what term is +4 anyway?

$\bf n^{th}\textit{ term of a geometric sequence}\\\\a_n=a_1\cdot r^{n-1}\qquad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\a_n=+4\end{cases}$

$\bf 4=512\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{4}{512}=\left( \cfrac{1}{2} \right)^{n-1}\\\\\\\cfrac{1}{128}=\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{1}{2^7}=\left( \cfrac{1}{2} \right)^{n-1}\implies 2^{-7}=\left( 2^{-1}\right)^{n-1}\\\\\\(2^{-1})^7=(2^{-1})^{n-1}\implies 7=n-1\implies \boxed{8=n}$

so is the 8th term, then, let's find the Sum of the first 8 terms.

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\n=8\end{cases}$

$\bf S_8=512\left[ \cfrac{1-\left( \frac{1}{2} \right)^8}{1-\frac{1}{2}} \right]\implies S_8=512\left(\cfrac{1-\frac{1}{256}}{\frac{1}{2}} \right)\implies S_8=512\left(\cfrac{\frac{255}{256}}{\frac{1}{2}} \right)\\\\\\S_8=512\cdot \cfrac{255}{128}\implies S_8=1020$

7 0

3 years ago

Help on the last 2?

ser-zykov [4K]

4x, 8, 20

X/6, 1/3, 5/6

4 0

3 years ago

Approximate √1800 by the nearest hundredth.---- EXPLAIN HOW YOU GOT IT PLEASEEEEE

DENIUS [597]

42.43 you would just square root it by typing in 1800 then hitting the radical sign. Hope this helped

7 0

3 years ago