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IgorLugansk [536]
2 years ago
5

I need someone to Evaluate 271,000√3. Make it into a fraction

Mathematics
2 answers:
n200080 [17]2 years ago
6 0
271000√3
=469385.76885
=46938576885/100000
=9387715377/20000

Hope my answer helped u :)
Debora [2.8K]2 years ago
3 0

Answer:

6 1615/15377

Step-by-step explanation:

271,000√3 = 469385.768851

Turn that into a fraction 469385/ 768851

Simplify.

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4 0
2 years ago
Rename 5/6 and 14/15 using the least common denominator.
baherus [9]

Answer:

\frac{25}{30}~and~\frac{28}{30}

  • Multiply 5 by 5 to get your first parameter.

5 * 5 = 25

  • Multiply 6 by 5 to get the denominator, or your second parameter.

5 * 6 = 30

  • For the second fraction, \frac{14}{15}, you need to multiply both parameters by 2, similar to before, but we now must use a different number, otherwise, the denominators will not be the same.

14 * 2 = 28

  • Now, multiply 15 by 2

15 * 2 = 30

  • The last step is to put these numbers you gathered into fractions. The bigger number always goes on the bottom, referred to as the denominator, while the smaller number, referred to as the numerator, always goes on the top.

25~and~30 -- > \frac{25}{30}

28~and~30-- > \frac{28}{30}

________________________________________________________

Finally, the problem is solved. Now that the problem is solved, we review what we just learned <em>not through more problems, though.</em>

________________________________________________________

<h3>What have we learned?</h3>

We learned how to efficiently make fractions' deominators match.

Questions related to this topic? Ask me in the comments box, please!

8 0
2 years ago
Which table shows a proportional relationship between x and y ?
insens350 [35]

Answer:

Table C

Step-by-step explanation:

Given

Table A to D

Required

Which shows a proportional relationship

To do this, we make use of:

k = \frac{y}{x}

Where k is the constant of proportionality.

In table (A)

x = 2, y = 4

k = \frac{y}{x}

k = \frac{4}{2}

k = 2

x = 4, y = 9

k = \frac{y}{x}

k = \frac{9}{4}

k = 2.25

Both values of k are different. Hence, no proportional relationship

In table (B)

x = 3, y = 4

k = \frac{y}{x}

k = \frac{4}{3}

k = 1.33

x = 9, y = 16

k = \frac{y}{x}

k = \frac{16}{9}

k = 1.78

Both values of k are different. Hence, no proportional relationship

In table (C):

x = 4, y = 12

k = \frac{y}{x}

k = \frac{12}{4}

k = 3

x = 5, y = 15

k = \frac{y}{x}

k = \frac{15}{5}

k = 3

x = 6, y = 18

k = \frac{y}{x}

k = \frac{18}{6}

k = 3

This shows a proportional relationship because all values of k are the same for this table

7 0
3 years ago
Help, stuck on this math problem!
alexgriva [62]

Answer: $498.08

Please Mark me as Brainliest

6 0
3 years ago
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